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甲基自由基与氦气的转动非弹性碰撞的理论研究。

Theoretical investigation of rotationally inelastic collisions of the methyl radical with helium.

机构信息

Department of Chemistry, The Johns Hopkins University, Baltimore, Maryland 21218-2685, USA.

出版信息

J Chem Phys. 2011 Aug 14;135(6):064306. doi: 10.1063/1.3624525.

Abstract

Rotationally inelastic collisions of the CH(3) molecule in its ground X(2)A(2)'' electronic state have been investigated. We have determined a potential energy surface (PES) for the interaction of rigid CH(3), frozen at its equilibrium geometry, with a helium atom, using a coupled-cluster method that includes all single and double excitations, as well as perturbative contributions of connected triple excitations [RCCSD(T)]. The anisotropy of the PES is dominated by repulsion of the helium by the hydrogen atoms. The dissociation energy D(e) was computed to equal 27.0 cm(-1). At the global minimum, the helium atom lies in the CH(3) plane between two C-H bonds at an atom-molecule separation R = 6.52 bohr. Cross sections for collision-induced rotational transitions have been determined through quantum scattering calculations for both nuclear spin modifications. Rotationally inelastic collisions can cause a change in the rotational angular momentum n and its body-frame projection k. Because of the anisotropy of the PES due to the hydrogen atoms, there is a strong propensity for Δk = ±3 transitions. Thermal rate constants for state-specific total collisional removal have also been determined.

摘要

CH(3)分子在其基态 X(2)A(2)''电子态下的旋转非弹性碰撞已经过研究。我们使用包含所有单重和双重激发以及相关三重激发的耦合簇方法 [RCCSD(T)],确定了刚性 CH(3)与氦原子相互作用的势能面 (PES),其中 CH(3) 固定在其平衡几何形状。PES 的各向异性主要由氢原子排斥氦原子主导。解离能 D(e)计算为 27.0 cm(-1)。在全局最小值处,氦原子位于 CH(3) 平面内,两个 C-H 键之间,原子-分子分离距离 R = 6.52 bohr。通过量子散射计算,针对两种核自旋修正确定了碰撞诱导的转动跃迁的截面。由于氢原子导致的 PES 各向异性,存在强烈的倾向使 Δk = ±3 跃迁。也确定了特定态总碰撞消除的热速率常数。

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