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(PNN)-Ru(II) 氢化物配合物催化的醇和胺的脱氢偶联反应的深入研究:不寻常的金属-配体协同作用。

Insights into dehydrogenative coupling of alcohols and amines catalyzed by a (PNN)-Ru(II) hydride complex: unusual metal-ligand cooperation.

机构信息

Institute of Theoretical and Computational Chemistry, School of Chemistry and Chemical Engineering, Key Laboratory of Mesoscopic Chemistry of Ministry of Education, Nanjing University, Nanjing, 210093, PR China.

出版信息

Inorg Chem. 2011 Nov 7;50(21):10572-80. doi: 10.1021/ic200205e. Epub 2011 Sep 26.

Abstract

Density functional theory calculations were performed to elucidate the mechanism of dehydrogenative coupling of primary alcohols and amines mediated by a PNN-Ru(II) hydride complex (PNN = (2-(di-tert-butylphosphinomethyl)-6-(diethylaminomethyl)pyridine)). A plausible reaction pathway was proposed which contains three stages: (1) The alcohol dehydrogenation reaction to generate the aldehyde and H(2); (2) The aldehyde-amine condensation reaction to form the hemiaminal intermediate; (3) The dehydrogenation process of the hemiaminal intermediate to yield the final amide product with the liberation of H(2). The first and third stages occur via a similar pathway: (a) Proton transfer from the substrate to the PNN ligand; (b) Intramolecular rearrangement of the deprotonated substrate to form an anagostic complex; (c) Hydride transfer from the deprotonated substrate to the Ru center to yield the trans-dihydride intermediate and the aldehyde (or amide); (d) Benzylic proton migration from the PNN ligand to the metal center forming a dihydrogen complex and subsequent H(2) liberation to regenerate the catalyst. In all these steps, the metal-ligand cooperation plays an essential role. In proton transfer steps (a) and (d), the metal-ligand cooperation is achieved through the aromatization/dearomatization processes of the PNN ligand. While in steps (b) and (c), their collaboration are demonstrated by the formation of an anagostic interaction between Ru and the C-H bond and two ionic hydrogen bonds supported by the PNN ligand.

摘要

密度泛函理论计算阐明了由 PNN-Ru(II)氢化物配合物(PNN = (2-(二-叔丁基膦基甲基)-6-(二乙基氨甲基)吡啶))介导的伯醇和胺的脱氢偶联反应的机理。提出了一个可能的反应途径,包含三个阶段:(1)醇的脱氢反应生成醛和 H(2);(2)醛-胺缩合反应形成半亚胺中间体;(3)半亚胺中间体的脱氢过程生成最终的酰胺产物,并释放 H(2)。第一和第三阶段通过类似的途径发生:(a)从底物到 PNN 配体的质子转移;(b)去质子化底物的分子内重排形成螯合复合物;(c)从去质子化的底物向 Ru 中心转移氢化物,生成反式二氢化物中间体和醛(或酰胺);(d)从 PNN 配体到金属中心的苄基质子迁移形成双氢复合物,并随后释放 H(2)以再生催化剂。在所有这些步骤中,金属-配体的协同作用起着至关重要的作用。在质子转移步骤(a)和(d)中,金属-配体的协同作用是通过 PNN 配体的芳构化/去芳构化过程实现的。而在步骤(b)和(c)中,它们的协作通过 Ru 与 C-H 键之间形成的螯合相互作用以及由 PNN 配体支持的两个离子氢键来证明。

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