Gangadharan Rajeswari, Sethusankar K, Selvakumar Raman, Bakthadoss Manickam
Acta Crystallogr Sect E Struct Rep Online. 2011 Oct 1;67(Pt 10):o2738. doi: 10.1107/S1600536811037925. Epub 2011 Sep 30.
In the title compound, C(18)H(14)Cl(2)O(4), the mean planes of the methyl acrylate unit and the phenyl ring of the benzaldehyde are approximately orthogonal to each other, making a dihedral angle of 83.31 (6)°. The O atom of the aldehyde group is displaced significantly from the phenyl ring plane by 0.226 (2) Å. The methyl acrylate group adopts an E conformation. In the crystal, inversion dimers linked by pairs of C-H⋯O hydrogen bonds generate R(2) (2)(24) loops.
在标题化合物C₁₈H₁₄Cl₂O₄中，丙烯酸甲酯单元的平均平面与苯甲醛的苯环平面大致相互正交，二面角为83.31（6）°。醛基的O原子相对于苯环平面显著位移0.226（2）Å。丙烯酸甲酯基团呈E构象。在晶体中，通过成对的C—H⋯O氢键连接的反演二聚体形成R₂²（24）环。
