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[Cp*RuCl((I)Pr2PSX)](X = 吡啶基、喹啉基)促进醇中 O-H 键的活化:制备钌(IV)氢(烷氧基)衍生物的一种途径。

Facile O-H bond activation in alcohols by [Cp*RuCl((I)Pr2PSX)] (X = pyridyl, quinolyl): a route to ruthenium(IV) hydrido(alkoxo) derivatives.

机构信息

Departamento de Ciencia de Materiales e Ingeniería Metalúrgica y Química Inorgánica, Facultad de Ciencias, Universidad de Cádiz, 11510 Puerto Real, Cádiz, Spain.

出版信息

Inorg Chem. 2011 Dec 19;50(24):12399-401. doi: 10.1021/ic201912b. Epub 2011 Nov 16.

Abstract

The complexes [CpRuCl((i)Pr(2)PSX)] (X = pyridyl, quinolyl) react directly with alcohols ROH (R = Me, Et, (i)Pr, (n)Pr) and NaBPh(4), affording the novel cationic hydrido(alkoxo) derivatives [CpRuH(OR)((i)Pr(2)PSX)][BPh(4)]. These ruthenium(IV) compounds result from the formal oxidative addition of the alcohol to the 16-electron fragment {Cp*Ru((i)Pr(2)PSX)}, generated in situ upon chloride dissociation. The hydrido(alkoxo) complexes are reversibly deprotonated by a strong base such as KOBu(t), yielding the neutral alkoxides [CpRu(OR)((i)Pr(2)PSX)], which are remarkably stable toward β elimination and do not generate the corresponding hydrides. The hydrido(alkoxo) complexes undergo a slow electron-transfer process, releasing H(2) and generating the dinuclear ruthenium(III) complex [{CpRu(κ(2)-N,S-μ S-SC(5)H(4)N)}(2)]BPh(4). In this species, the Ru-Ru separation is very short and consistent with what is expected for a Ru≡Ru triple bond.

摘要

复合物 [CpRuCl((i)Pr(2)PSX)](X = 吡啶基,喹啉基)可直接与醇 ROH(R = Me、Et、(i)Pr、(n)Pr)和 NaBPh(4)反应,生成新型的阳离子氢(烷氧基)衍生物 [CpRuH(OR)((i)Pr(2)PSX)][BPh(4)]。这些钌(IV)化合物是通过醇对原位生成的 16 电子片段 {Cp*Ru((i)Pr(2)PSX)} 的形式氧化加成得到的,氯离子的解离会生成该片段。氢(烷氧基)配合物可被强碱如 KOBu(t)可逆地去质子化,生成中性烷氧基[CpRu(OR)((i)Pr(2)PSX)],其对β消除具有显著的稳定性,不会生成相应的氢化物。氢(烷氧基)配合物经历缓慢的电子转移过程,释放出 H(2)并生成双核钌(III)配合物 [{CpRu(κ(2)-N,S-μ S-SC(5)H(4)N)}(2)]BPh(4)。在该物种中,Ru-Ru 间距非常短,与 Ru≡Ru 三键的预期值一致。

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