van der Hoeven N, Hemerik L
Institute of Theoretical Biology, University of Leiden, The Netherlands.
J Theor Biol. 1990 Oct 21;146(4):467-82. doi: 10.1016/s0022-5193(05)80373-x.
A stochastic model is formulated to determine the optimal strategy for a solitary parasitoid which has discovered an already parasitized host. The model assumes that the parasitoid can count both the number of eggs already present in a host and the number of conspecifics searching in the same patch. The survival probability of an egg is assumed to depend on the total number of eggs in a host. The decision to (super)parasitize depends both on the degree to which the discovered host already is parasitized and on the number of conspecific females searching in the same patch. We consider both the case that egg laying does not involve any costs for the parasitoid and the case that it involves some marginal costs. Uniform behaviour of all the conspecific parasitoids in a patch, i.e. laying one additional egg in all encountered larvae containing a particular number of eggs, appears to be a pure evolutionary stable strategy (ESS). If either the probability that a parasitoid emerges from a host decreases with an increasing degree of parasitism, at least from a particular number of eggs onwards, or if parasitism involves marginal costs, the maximum number of eggs for which it is still profitable to superparasitize a host once more is limited. This number increases with the number of conspecifics searching in the patch. Large marginal costs (i.e. the expected gain of not parasitizing now) decrease the profit of superparasitism. For newly emerged parasitoids the rejection of an already parasitized host is not advantageous as long as the marginal costs of parasitism are small, because the host can never contain an egg of its own.
构建了一个随机模型,以确定已发现被寄生宿主的独居寄生蜂的最优策略。该模型假设寄生蜂既能计算宿主中已有的卵数,也能计算在同一斑块中搜索的同种个体数量。假定一个卵的存活概率取决于宿主中的卵总数。(超级)寄生的决策既取决于已发现宿主的被寄生程度,也取决于在同一斑块中搜索的同种雌性数量。我们考虑了产卵对寄生蜂无任何成本的情况以及涉及一些边际成本的情况。斑块中所有同种寄生蜂的一致行为,即在所有遇到的含有特定数量卵的幼虫中再产一个卵,似乎是一种纯粹的进化稳定策略(ESS)。如果要么寄生蜂从宿主中羽化的概率随着寄生程度的增加而降低,至少从特定数量的卵开始是这样,要么如果寄生涉及边际成本,那么再次对宿主进行超级寄生仍有利可图的最大卵数是有限的。这个数量随着在斑块中搜索的同种个体数量增加而增加。巨大的边际成本(即现在不寄生的预期收益)会降低超级寄生的利润。对于新羽化的寄生蜂来说,只要寄生的边际成本很小,拒绝已被寄生的宿主就没有优势,因为宿主永远不会有它自己的卵。