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2-杂芳基吡啶与钯-膦配合物的反应性:根据杂原子和膦配体的性质分离得到不同的配合物。

Reactivity of 2-chalcogenopyridines with palladium-phosphine complexes: isolation of different complexes depending on the nature of chalcogen atom and phosphine ligand.

机构信息

Chemistry Division, Bhabha Atomic Research Centre, Mumbai-400 085, India.

出版信息

Dalton Trans. 2013 Jan 7;42(1):259-69. doi: 10.1039/c2dt30535f.

DOI:10.1039/c2dt30535f
PMID:23086471
Abstract

Reactions of either Pd(0) phosphine complexes with dipyridyldichalcogenides or [PdCl2(P∩P)] (P∩P = dppe, dppp) with pyridylchalcogenolate ions have been examined and a variety of Pd(II) complexes have been isolated and characterized. Oxidative addition of {SeC5H3(3-R)N}2 (R = H or Me) to [Pd(P∩P)2] (P∩P = dppe, dppp) gave either a mononuclear complex, [Pd{2-Se-C5H3(3-R)N}2(P∩P)] (for P∩P/R: dppe/H or Me; dppp/H) or a cationic binuclear complex, [Pd2{μ-SeC5H3(3-Me)N}2(dppp)2]2+ (4b) (R = Me) whereas reactions involving the tellurium analogue exclusively afforded trinuclear complexes, [Pd3(μ-Te)2(P∩P)3]Cl2 (P∩P = dppe (2) or dppp (6)). The latter was also obtained in the substitution reaction between [PdCl2(P∩P)] and NaTeC5H3(3-R)N. The substitution reactions between [PdCl2(dppe)] and Pb{EC5H3(3-R)N}2 yielded mononuclear complexes, [Pd{2-E-C5H3(3-R)N}2(dppe)] (1a–1e) (E = S, Se or Te) while in the case of [PdCl2(dppp)], the reactions resulted in the formation of mono-, bi- and tri- nuclear complexes depending on the nature of the chalcogen atom (E = S, Se or Te) and the substituent on the pyridyl ring (R = H or Me). Treatment of dipyridyl ditellurides, {TeC5H3(3-R)N}2 (R = H or Me), with [Pd(PPh3)4] gave expected tellurolate complexes, [Pd{2-TeC5H3(3-R)N}2(PPh3)2] (7a, 7b) which on prolonged standing in CDCl3 solution gave green crystals of [PdCl{2-Te(Cl)2C5H3(3-Me)N}(PPh3)] (9). The molecular structures of {TeC5H3(3-Me)N}2, [Pd2{μ-TeC5H3(3-Me)N}2(dppp)2]Cl2·3H2O (5·3H2O), [Pd3(μ-Te)2(dppp)3]Cl2·3CHCl3 (6·3CHCl3) and [PdCl{2-Te(Cl)2C5H3(3-Me)N}(PPh3)] (9) were established by single crystal X-ray diffraction analyses.

摘要

钯(0)膦配合物与二吡啶二杂二硫化物或[PdCl2(P∩P)](P∩P = dppe,dppp)与吡啶杂硫醇离子的反应已经被研究过,并且已经分离和表征了各种 Pd(II)配合物。{SeC5H3(3-R)N}2(R = H 或 Me)对[Pd(P∩P)2](P∩P = dppe,dppp)的氧化加成反应分别得到单核配合物[Pd{2-Se-C5H3(3-R)N}2(P∩P)](对于 P∩P/R:dppe/H 或 Me;dppp/H)或阳离子双核配合物[Pd2{μ-SeC5H3(3-Me)N}2(dppp)2]2+(4b)(R = Me),而涉及碲类似物的反应仅得到三核配合物[Pd3(μ-Te)2(P∩P)3]Cl2(P∩P = dppe(2)或 dppp(6))。后者也可以在[PdCl2(P∩P)]和 NaTeC5H3(3-R)N 之间的取代反应中获得。[PdCl2(dppe)]和 Pb{EC5H3(3-R)N}2 之间的取代反应生成单核配合物[Pd{2-E-C5H3(3-R)N}2(dppe)](1a–1e)(E = S、Se 或 Te),而对于[PdCl2(dppp)],反应的结果取决于杂原子(E = S、Se 或 Te)和吡啶环上取代基(R = H 或 Me)的性质,形成单核、双核和三核配合物。二吡啶二碲化物{TeC5H3(3-R)N}2(R = H 或 Me)与[Pd(PPh3)4]的反应得到预期的碲醇盐配合物[Pd{2-TeC5H3(3-R)N}2(PPh3)2](7a,7b),这些配合物在 CDCl3 溶液中长时间放置后会生成绿色的[PdCl{2-Te(Cl)2C5H3(3-Me)N}(PPh3)](9)晶体。通过单晶 X 射线衍射分析确定了{TeC5H3(3-Me)N}2、[Pd2{μ-TeC5H3(3-Me)N}2(dppp)2]Cl2·3H2O(5·3H2O)、[Pd3(μ-Te)2(dppp)3]Cl2·3CHCl3(6·3CHCl3)和[PdCl{2-Te(Cl)2C5H3(3-Me)N}(PPh3)](9)的分子结构。

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