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Chiral tripodal ligand containing three N-heterocyclic donor functions and its copper complexes: crystallization of [LCu(I)]2(2+)/[L2Cu(II)](2+) stereoisomers and tyrosinase activity.

作者信息

Arnold Aline, Limberg Christian, Metzinger Ramona

机构信息

Humboldt-Universität zu Berlin , Institut für Chemie, Brook-Taylor-Straβe 2, 12489 Berlin, Germany.

出版信息

Inorg Chem. 2012 Nov 19;51(22):12210-7. doi: 10.1021/ic301391s. Epub 2012 Oct 30.

DOI:10.1021/ic301391s
PMID:23110334
Abstract

A novel chiral ligand system L containing one pyridyl and two imidazolyl donor functions has been synthesized and investigated with respect to its Cu(I) and Cu(II) coordination chemistry. Reaction with [Cu(MeCN)4]PF6 and [Cu(MeCN)4]OTf led to the dimeric complexes [LCu]2X2 (1, X = PF6; 2, X = OTf) with the ligands L in different configurations (R,S). The ligand matrix formed in these complexes can also host a Cu(II) ion instead of two Cu(I) ions so that mixed crystals of [L2Cu]X2 and [LCu]2X2 can be produced. The pure compounds [L2Cu]X2 (3, X = PF6; 4, X = OTf) can be obtained by treatment of 1 and 2 with O2 in acetonitrile, respectively. From the corresponding solution 3 crystallizes with the two L molecules in different configurations, while 4 crystallizes with the ligands in (S,S) or (R,R) configurations, respectively. Crystals containing the analogous diastereomers of 3 were obtained, besides those isolated previously, when this compound was synthesized by reaction of 1 with AgPF6. On treating 2 with O2 as the oxidant in acetonitrile, besides formation of 4, additional evidence for oxygenation of L to L(ox), where one of the original phenyl units corresponds to a phenolate function, was found: The dinuclear complex L(ox)Cu(OH)(OTf)CuL (5) was isolated as the final product of O2 activation and conversion, which resembles the one of tyrosinase. In acetonitrile 5 reacts further to give 4 and L(ox)2Cu22 (6), and hence, product mixtures are obtained. In CH2Cl2 decomposition can be avoided, and hence, changing the solvent from acetonitrile to CH2Cl2 leads to selective formation of 5.

摘要

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