Luo Xu-Jian, Zhang Chuan-Hui, Zhou Jie, Liu Yan-Cheng
College of Chemistry and Chemical Engineering, Central South University, Changsha 410083, People's Republic of China.
Acta Crystallogr Sect E Struct Rep Online. 2013 Apr 20;69(Pt 5):m278-9. doi: 10.1107/S1600536813010118. Print 2013 May 1.
The reaction of 4-chloro-2-(quinolin-8-yl-imino-meth-yl)phenol (HClQP) with cobalt(II) dichloride hexa-hydrate in methanol/chloro-form under solvothermal conditions yielded the title compound, [Co(C16H10ClN2O)2][CoCl3(CH3OH)]. The Co(III) atom is six-coordinated in a slightly distorted octa-hedral geometry by four N atoms and two O atoms of two tridentate HClQP ligands, which are nearly perpendicular to each other, making a dihedral angle of 86.95°. The Co(II) atom is four-coordinated by three Cl atoms and one O atom from a methanol ligand in a distorted tetra-hedral geometry. The crystal packing is consolidated by inter-molecular O-H⋯Cl, C-H⋯Cl and C-H⋯O hydrogen bonds, forming a three-dimensional supra-molecular structure, in which [Co(II)Cl3(CH3OH)] anions are connected via O-H⋯Cl and C-H⋯Cl hydrogen bonds into centrosymmetric dimers. Neighboring cobalt(III) complexes form dimers through C-H⋯O hydrogen bonds, as well as π-π stacking [centroid-centroid distances = 3.30 (2) Å] between the planar quinoline systems of one HClQP ligand and the phenolate ring of another.
4-氯-2-(喹啉-8-基亚氨基甲基)苯酚(HClQP)与二氯化钴六水合物在甲醇/氯仿的溶剂热条件下反应,得到标题化合物[Co(C₁₆H₁₀ClN₂O)₂][CoCl₃(CH₃OH)]。Co(III)原子由两个三齿HClQP配体的四个N原子和两个O原子以略微扭曲的八面体几何构型六配位,这两个配体几乎相互垂直,二面角为86.95°。Co(II)原子由一个甲醇配体的三个Cl原子和一个O原子以扭曲的四面体几何构型四配位。晶体堆积通过分子间的O-H⋯Cl、C-H⋯Cl和C-H⋯O氢键得以巩固,形成三维超分子结构,其中[Co(II)Cl₃(CH₃OH)]阴离子通过O-H⋯Cl和C-H⋯Cl氢键连接成中心对称二聚体。相邻的钴(III)配合物通过C-H⋯O氢键以及一个HClQP配体的平面喹啉体系与另一个的酚盐环之间的π-π堆积[质心-质心距离 = 3.30 (2) Å]形成二聚体。