Datta Riya, Ramya V, Sithambaresan M, Kurup M R Prathapachandra
Department of Chemistry, Christ University, Hosur Road, Bangalore 560 029, India.
Acta Crystallogr Sect E Struct Rep Online. 2013 Sep 18;69(Pt 10):o1549. doi: 10.1107/S1600536813025075. eCollection 2013.
The title compound, C15H13N3O3, exists in the E conformation with respect to the azo-methane C=N double bond. The pyridyl and phenyl rings form dihedral angles of 35.67 (8) and 36.65 (7)°, respectively with the central C(=O)N2C unit. In the crystal, N-H⋯O and C-H⋯O hydrogen bonds connect the mol-ecules into chains along the b axis. Another C-H⋯O inter-action connects mol-ecules along the c-axis direction, forming layers.
标题化合物C₁₅H₁₃N₃O₃中,偶氮甲烷C=N双键呈E构型。吡啶环和苯环与中心C(=O)N₂C单元分别形成35.67 (8)°和36.65 (7)°的二面角。在晶体中,N-H⋯O和C-H⋯O氢键将分子沿b轴连接成链。另一种C-H⋯O相互作用沿c轴方向连接分子,形成层状结构。