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通过苯基自由基(C6H5)与异戊二烯(CH2C(CH3)CHCH2)和1,3 - 戊二烯(CH2CHCHCHCH3)的交叉束反应形成2 - 甲基 - 1,4 - 二氢萘异构体和1 - 甲基 - 1,4 - 二氢萘异构体。

Formation of 2- and 1-methyl-1,4-dihydronaphthalene isomers via the crossed beam reactions of phenyl radicals (C6H5) with isoprene (CH2C(CH3)CHCH2) and 1,3-pentadiene (CH2CHCHCHCH3).

作者信息

Yang Tao, Muzangwa Lloyd, Parker Dorian S N, Kaiser Ralf I, Mebel Alexander M

机构信息

Department of Chemistry, University of Hawaii at Manoa, Honolulu, HI 96822, USA.

出版信息

Phys Chem Chem Phys. 2015 Jan 7;17(1):530-40. doi: 10.1039/c4cp04612a.

Abstract

Crossed molecular beam reactions were exploited to elucidate the chemical dynamics of the reactions of phenyl radicals with isoprene and with 1,3-pentadiene at a collision energy of 55 ± 4 kJ mol(-1). Both reactions were found to proceed via indirect scattering dynamics and involve the formation of a van-der-Waals complex in the entrance channel. The latter isomerized via the addition of the phenyl radical to the terminal C1/C4 carbon atoms through submerged barriers forming resonantly stabilized free radicals C11H13, which then underwent cis-trans isomerization followed by ring closure. The resulting bicyclic intermediates fragmented via unimolecular decomposition though the atomic hydrogen loss via tight exit transition states located 30 kJ mol(-1) above the separated reactants in overall exoergic reactions forming 2- and 1-methyl-1,4-dihydronaphthalene isomers. The hydrogen atoms are emitted almost perpendicularly to the plane of the decomposing complex and almost parallel to the total angular momentum vector ('sideways scattering') which is in strong analogy to the phenyl-1,3-butadiene system studied earlier. RRKM calculations confirm that 2- and 1-methyl-1,4-dihydronaphthalene are the dominating reaction products formed at levels of 97% and 80% in the reactions of the phenyl radical with isoprene and 1,3-pentadiene, respectively. This barrier-less formation of methyl-substituted, hydrogenated PAH molecules further supports our understanding of the formation of aromatic molecules in extreme environments holding temperatures as low as 10 K.

摘要

利用交叉分子束反应来阐明在55±4 kJ mol⁻¹的碰撞能量下,苯基自由基与异戊二烯以及与1,3 - 戊二烯反应的化学动力学。发现这两个反应均通过间接散射动力学进行,且在入口通道中涉及范德华复合物的形成。后者通过苯基自由基加成到末端C1/C4碳原子上,经淹没势垒异构化形成共振稳定自由基C11H13,然后进行顺反异构化,接着闭环。在总体放能反应中,生成的双环中间体通过单分子分解碎片化,通过位于比分离反应物高30 kJ mol⁻¹的紧密出口过渡态损失原子氢,形成2 - 甲基 - 1,4 - 二氢萘和1 - 甲基 - 1,4 - 二氢萘异构体。氢原子几乎垂直于分解复合物的平面发射,且几乎平行于总角动量矢量(“侧向散射”),这与早期研究的苯基 - 1,3 - 丁二烯体系非常相似。RRKM计算证实,在苯基自由基与异戊二烯和1,3 - 戊二烯的反应中,2 - 甲基 - 1,4 - 二氢萘和1 - 甲基 - 1,4 - 二氢萘分别以97%和80%的水平成为主要反应产物。这种甲基取代的氢化多环芳烃分子的无势垒形成进一步支持了我们对在低至10 K温度的极端环境中芳香分子形成的理解。

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