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[3-(1H-苯并咪唑-2-基)丙酸根-κN(3)][3-(1H-苯并咪唑-2-基)丙酸-κN(3)]铜(I)的晶体结构

Crystal structure of [3-(1H-benzimidazol-2-yl)propano-ato-κN (3)][3-(1H-benzimid-azol-2-yl)propanoic acid-κN (3)]copper(I).

作者信息

Liu Zhimin, Zheng Shengrun, Feng Sisi

机构信息

School of Chemistry and Chemical Engineering, Shanxi University, Taiyuan 030006, People's Republic of China.

Institute of Special Materials & School of Chemistry and Environment, South China Normal University, Guangzhou 510006, People's Republic of China.

出版信息

Acta Crystallogr E Crystallogr Commun. 2015 Jan 1;71(Pt 1):m5-6. doi: 10.1107/S2056989014026656.

DOI:10.1107/S2056989014026656
PMID:25705474
原文链接:https://pmc.ncbi.nlm.nih.gov/articles/PMC4331864/
Abstract

In the title compound, [Cu(C10H9N2O2)(C10H10N2O2)], the Cu(I) ion is situated at a crystallographic centre of inversion and is coordinated in a linear environment by two benzimidazole N atoms from two symmetry-related 2-propanoic-1H-benzimidazole ligands. The ligands are disordered in a sense that statistically one of the carb-oxy-lic acid groups in each mol-ecule is deprotonated. In the crystal, O-H⋯O hydrogen bonds link the mol-ecules into chains along the a-axis direction. These chains are additionally linked into infinite two-dimensional networks in the ab plane by N-H⋯O hydrogen bonds.

摘要

在标题化合物[Cu(C₁₀H₉N₂O₂)(C₁₀H₁₀N₂O₂)]中,Cu(I)离子位于一个晶体学对称中心,由来自两个对称相关的2-丙酸-1H-苯并咪唑配体的两个苯并咪唑N原子在直线型环境中配位。从统计学角度看,每个分子中的一个羧酸基团去质子化,因此配体是无序的。在晶体中,O—H⋯O氢键将分子沿a轴方向连接成链。这些链通过N—H⋯O氢键在ab平面上进一步连接成无限的二维网络。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/9749/4331864/5cf183abf77c/e-71-000m5-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/9749/4331864/7416fac2fab7/e-71-000m5-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/9749/4331864/5cf183abf77c/e-71-000m5-fig2.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/9749/4331864/7416fac2fab7/e-71-000m5-fig1.jpg
https://cdn.ncbi.nlm.nih.gov/pmc/blobs/9749/4331864/5cf183abf77c/e-71-000m5-fig2.jpg

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