Smith J B, Dwyer S D, Smith L
Department of Pharmacology, School of Medicine, University of Alabama, Birmingham 35294.
J Biol Chem. 1989 May 25;264(15):8723-8.
Changing extracellular pH (pHo) from 7.4 to 6.1 increased [3H]inositol bis- and trisphosphates approximately 10- and 5-fold, respectively, in 15 s in human fibroblasts. [3H]Inositol phosphate increased less rapidly than the polyphosphates. Bradykinin similarly increased [3H]inositol phosphates. Shifting pHo from 7.4 to 6.0 evoked a large spike in cytosolic free Ca2+ [( Ca2+]i) which was primarily caused by the release of stored Ca2+. Changing pHo from 7.4 to 6.0 decreased cytoplasmic pH to approximately 7.0. Moderate decreases in intracellular pH had no effect on [Ca2+]i or 45Ca2+ efflux. Decreasing pHo strikingly increased 45Ca2+ efflux and decreased total cell Ca2+ similarly to bradykinin. Changing pHo from 7.4 to approximately 6.4 produced half-maximal effects on [Ca2+]i, 45Ca2+ efflux, and total Ca2+. Cycling pHo between 7.4 and 6.0 produced repetitive decreases and increases in total Ca2+. Bradykinin released the Ca2+ which was reaccumulated after an acid pulse indicating that Ca2+ had returned to the hormone-sensitive pool. Decreasing pHo also released stored Ca2+ from coronary endothelial, neuroblastoma, and umbilical artery muscle cells, but not from rat aortic smooth muscle or human epidermoid carcinoma (A431) cells. We suggest that lowering pHo stimulates a phosphoinositidase-coupled receptor by protonating a functional group with a pKa near 6.5.
在人类成纤维细胞中,将细胞外pH(pHo)从7.4降至6.1,在15秒内使[3H]肌醇二磷酸和三磷酸分别增加了约10倍和5倍。[3H]肌醇磷酸的增加速度比多磷酸慢。缓激肽同样增加了[3H]肌醇磷酸。将pHo从7.4变为6.0会引起胞质游离Ca2+([Ca2+]i)的大幅峰值,这主要是由储存Ca2+的释放引起的。将pHo从7.4变为6.0会使细胞质pH降至约7.0。细胞内pH的适度降低对[Ca2+]i或45Ca2+流出没有影响。降低pHo显著增加了45Ca2+流出,并与缓激肽类似地降低了细胞总Ca2+。将pHo从7.4变为约6.4对[Ca2+]i、45Ca2+流出和总Ca2+产生了半数最大效应。在7.4和6.0之间循环pHo会使总Ca2+反复降低和增加。缓激肽释放的Ca2+在酸脉冲后重新积累,表明Ca2+已回到激素敏感池。降低pHo也会从冠状动脉内皮细胞、神经母细胞瘤细胞和脐动脉肌细胞中释放储存的Ca2+,但不会从大鼠主动脉平滑肌或人表皮样癌(A431)细胞中释放。我们认为,降低pHo通过使pKa接近6.5的官能团质子化来刺激磷酸肌醇酶偶联受体。