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基于复合抛物面聚光器和半球形透镜的用于可见光通信的光接收系统。

Optical receiving system based on a compound parabolic concentrator and a hemispherical lens for visible light communication.

作者信息

Wang Yun, Lan Tian, Ni Guoqiang

出版信息

Appl Opt. 2016 Dec 20;55(36):10229-10238. doi: 10.1364/AO.55.010229.

Abstract

We propose a scheme for designing a new optical receiving system that can reduce the received-energy spot size via integration of a compound parabolic concentrator with a hemispherical lens. SolidWorks is used to model the receiving system, while TracePro is employed for simulations. The field of view is set to 30° and the radius of the compound parabolic concentrator outlet is 5 mm, which is also the radius of the hemispherical lens. Ray-tracing results show that under the given simulation conditions, the radius of the spot area is reduced from 5 to 3 mm at the receiving system and the gain is 5.2. In regard to the relations between received power and the radius of the hemispherical lens R, and the received power and the distance d between the compound parabolic concentrator and hemispherical lens, our detailed analysis yields the following characteristics: (1) the received power increases as R increases, but decreases as d increases; (2) as R increases, the spot area increases and the received flux is dispersed over the receiving plane, which dispersion is disadvantageous for high-speed communication; (3) the gain of the receiving system also varies with R and d; (4) an increase in d leads to decrease in the received flux and gain when d>-2  mm. Based on these characteristics, we set R=5  mm and calculate the energy efficiency. We obtain maximum energy efficiencies for different detection areas.

摘要

我们提出了一种设计新型光接收系统的方案,该系统可通过将复合抛物面聚光器与半球形透镜集成来减小接收能量光斑尺寸。使用SolidWorks对接收系统进行建模,同时采用TracePro进行仿真。视场设置为30°,复合抛物面聚光器出口半径为5mm,这也是半球形透镜的半径。光线追踪结果表明,在给定的仿真条件下,接收系统处光斑区域的半径从5mm减小到3mm,增益为5.2。关于接收功率与半球形透镜半径R以及接收功率与复合抛物面聚光器和半球形透镜之间的距离d的关系,我们的详细分析得出以下特性:(1)接收功率随R的增加而增加,但随d的增加而减小;(2)随着R的增加,光斑面积增大,接收通量分散在接收平面上,这种分散不利于高速通信;(3)接收系统的增益也随R和d而变化;(4)当d > -2mm时,d的增加会导致接收通量和增益减小。基于这些特性,我们设置R = 5mm并计算能量效率。我们获得了不同检测区域的最大能量效率。

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