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基于光合作用电子传递的机理模型来量化光系统之间激发能的分布。

Quantification of excitation energy distribution between photosystems based on a mechanistic model of photosynthetic electron transport.

机构信息

Graduate School of Agricultural and Life Sciences, The University of Tokyo, Yayoi, Bunkyo, Tokyo, 113-8657, Japan.

出版信息

Plant Cell Environ. 2018 Jan;41(1):148-159. doi: 10.1111/pce.12986. Epub 2017 Aug 17.

DOI:10.1111/pce.12986
PMID:28548208
Abstract

Absorbed light energy is converted into excitation energy. The excitation energy is distributed to photosystems depending on the wavelength and drives photochemical reactions. A non-destructive, mechanistic and quantitative method for estimating the fraction of the excitation energy distributed to photosystem II (f) was developed. For the f values for two simultaneously provided actinic lights (ALs) with different spectral distributions to be estimated, photochemical yields of the photosystems were measured under the ALs and were then fitted to an electron transport model assuming the balance between the electron transport rates through the photosystems. For the method to be tested using leaves with different properties in terms of the long-term and short-term acclimation (adjustment of photosystem stoichiometry and state transition, respectively), the f values for red and far-red light (R and FR) were estimated in leaves grown (1 week) under white light without and with supplemental FR and adapted (10 min) to R without and with supplemental FR. The f values for R were clearly greater than those for FR and those of leaves grown with and adapted to supplemental FR tended to be higher than the controls. These results are consistent with previous studies and therefore support the validity of the proposed method.

摘要

被吸收的光能被转化为激发能。激发能根据波长分配给光系统,并驱动光化学反应。开发了一种非破坏性、机械和定量的方法来估计激发能分配给光系统 II (f)的分数。为了估计两个同时提供的具有不同光谱分布的光化学有效光 (AL) 的 f 值,在 AL 下测量光系统的光化学产量,然后根据电子传递模型进行拟合,该模型假设通过光系统的电子传递速率之间的平衡。为了使用在长期和短期驯化方面具有不同特性的叶片(分别调整光系统的化学计量和状态转变)来测试该方法,在没有和有补充 FR 的白光下生长 (~1 周) 的叶片中估计了红光和远红光 (R 和 FR) 的 f 值,以及在没有和有补充 FR 的情况下适应 R。R 的 f 值明显大于 FR 的 f 值,适应和不适应补充 FR 的叶片的 f 值往往高于对照。这些结果与以前的研究一致,因此支持所提出方法的有效性。

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