Lundeen M, Chance B, Powers L
Biophys J. 1987 Apr;51(4):693-5, 697. doi: 10.1016/S0006-3495(87)83395-7.
The locations of the transmembrane helices in the 12 subunits of beef heart cytochrome oxidase were predicted with a modified form of the von Heijne-Blomberg hydrophobicity scale. Based on ∼20 residues per transmembrane helix, about 480 of the estimated 660 helical residues (36.8% of 1,793 total residues) are expected to be in transmembrane helices that have their axes tilted by a small angle α from the normal to the plane of the membrane. This angle is calculated to be ∼30°, based on the observed overall tilt angle θ of 39° obtained from circular dichroism (CD) measurements on multilamellar films, or about 25°, based on the observed tilt angle θ of 36° obtained from the infrared linear dichroism of films. For 21 residues per transmembrane helix, the calculated values of α become 32° and 28°, respectively, depending upon the value of θ used. Thus, a transmembrane helical tilt angle of ∼30° accounts for the predicted transmembrane stretches in cytochrome oxidase if 20-21 residues are sufficient to span the membrane. Additional helical residues in the lipid head region may deviate by a larger angle from the normal to the plane of the membrane in cytochrome oxidase.
运用改良版的冯·海涅-布洛姆伯格疏水性标度,预测了牛心细胞色素氧化酶12个亚基中跨膜螺旋的位置。基于每个跨膜螺旋约20个残基,估计的660个螺旋残基中约480个(占1793个总残基的36.8%)预计位于其轴与膜平面法线倾斜小角度α的跨膜螺旋中。根据对多层膜进行圆二色性(CD)测量得到的39°的观察到的整体倾斜角θ计算,该角度约为30°;或者根据从膜的红外线性二色性得到的36°的观察到的倾斜角θ计算,该角度约为25°。对于每个跨膜螺旋21个残基,根据所使用的θ值,计算出的α值分别变为32°和28°。因此,如果20 - 21个残基足以跨越膜,那么约30°的跨膜螺旋倾斜角可解释细胞色素氧化酶中预测的跨膜片段。细胞色素氧化酶中脂质头部区域的额外螺旋残基可能与膜平面法线的偏离角度更大。