Piene H, Myhre E S, Winnem B
Department of Biomedical Engineering, Faculty of Medicine, University of Trondheim, Norway.
Acta Physiol Scand. 1988 Aug;133(4):501-11. doi: 10.1111/j.1748-1716.1988.tb08434.x.
Under the assumption that a ventricle and its arterial load are normally matched according to work optimization, a relation between left ventricular (LV) mechanical performance as described by the slope (Emax) of the end systolic pressure-volume relationship (ESPVR), mean systolic pressure during ejection (mSLVP), and stroke volume (SV), is proposed: optimum Emax = E' = mSLVP/SV. Slope (Emax) was obtained, in 6 dogs and 9 rabbits, by establishing relations among ejected volume and LV diameter squared (D2) in control beats, and among pressure and D2 at end systole (ES) in series of beats of varying load, accomplished either by acute aortic constriction (AOC) or inferior caval occlusion (IVCO). Slope in dogs was also obtained by direct measurements of ventricular volume by a conductance catheter and the results were compared with the above method. A dimensionless index, alpha = Emax/E', (optimal value = 1.0) was calculated to indicate how well the ventricle and arterial system were matched. In dogs, E' = 10.9 +/- 2.1 mmHg ml-1, Emax = 8.1 +/- 2.6 (AOC) and 7.1 +/- 2.5 (IVCO), hence alpha = 0.79 +/- 0.23 (AOC) and 0.68 +/- 0.15 (IVCO). In rabbits, E' = 54.1 +/- 20.0 mmHg ml-1, Emax = 64.8 +/- 15.9 (mmHg ml-1), hence alpha = 1.23 +/- 0.33. Alpha = 1.0 fell outside the 95% confidence interval only in experiments of dogs subjected to IVCO.
假设根据功优化原理,心室及其动脉负荷通常是匹配的,那么可得出左心室(LV)机械性能(由收缩末期压力 - 容积关系(ESPVR)的斜率(Emax)描述)、射血期平均收缩压(mSLVP)和每搏输出量(SV)之间的关系:最佳Emax = E' = mSLVP/SV。在6只狗和9只兔子中,通过建立对照搏动中射血量与左心室直径平方(D2)之间的关系,以及在一系列不同负荷搏动(通过急性主动脉缩窄(AOC)或下腔静脉闭塞(IVCO)实现)的收缩末期(ES)压力与D2之间的关系,获得斜率(Emax)。狗的斜率也通过电导导管直接测量心室容积获得,并将结果与上述方法进行比较。计算了一个无量纲指数α = Emax/E'(最佳值 = 1.0),以指示心室和动脉系统的匹配程度。在狗中,E' = 10.9 +/- 2.1 mmHg ml-1,Emax = 8.1 +/- 2.6(AOC)和7.1 +/- 2.5(IVCO),因此α = 0.79 +/- 0.23(AOC)和0.68 +/- 0.15(IVCO)。在兔子中,E' = 54.1 +/- 20.0 mmHg ml-1,Emax = 64.8 +/- 15.9(mmHg ml-1),因此α = 1.23 +/- 0.33。仅在接受IVCO的狗的实验中,α = 1.0落在95%置信区间之外。