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手性螺旋二醇对映体的证据。使用 α,α'-双(三氟甲基)-9,10-蒽二甲醇作为手性溶剂,并通过与手性酸衍生化来区分。

Evidence of Enantiomers of Spiroglycol. Distinction by Using α,α'-Bis(trifluoromethyl)-9,10-anthracenedimethanol as a Chiral Solvating Agent and by Derivatization with Chiral Acids.

出版信息

J Org Chem. 2020 Jun 5;85(11):7247-7257. doi: 10.1021/acs.joc.0c00578. Epub 2020 May 27.

Abstract

Herein, we perform for the first time a preliminary NMR and computational study of the spiroglycol structure. Spiroglycol is a highly symmetrical molecule, but it should be chiral due to the presence of a chiral axis. The presence of two enantiomers was demonstrated performing NMR enantiodifferentiation experiments using α,α'-bis(trifluoromethyl)-9,10-anthracenedimethanol (ABTE) as a chiral solvating agent (CSA). The addition of 0.6 equiv of ABTE allows the differentiation of several spiroglycol proton signals. The lack of resolution observed in the proton spectrum can be tackled through the corresponding C NMR spectrum where a significant enantiodifferentiation at the spirocarbon atom was observed. In order to physically separate both enantiomers, a SPG derivatization with camphorsulfonic acid and Mosher's acid was performed affording the corresponding diastereoisomeric ester mixtures. Computations performed with the Gaussian16 package showed that the enantiodifferentiation is mainly due to the different compound thermodynamics stability.

摘要

本文首次对螺二醇结构进行了核磁共振(NMR)和计算研究。螺二醇是一个高度对称的分子,但由于存在手性轴,它应该是手性的。使用α,α'-双(三氟甲基)-9,10-蒽二甲醇(ABTE)作为手性溶剂(CSA)进行 NMR 对映体区分实验,证明了两种对映异构体的存在。添加 0.6 当量的 ABTE 可以区分几个螺二醇质子信号。在质子光谱中观察到的分辨率不足可以通过相应的 C NMR 光谱来解决,在 C NMR 光谱中观察到螺碳原子的显著对映体差异。为了将两种对映异构体物理分离,用樟脑磺酸和莫舍尔酸对 SPG 进行衍生化,得到相应的非对映异构体酯混合物。使用 Gaussian16 软件包进行的计算表明,对映体差异主要是由于化合物热力学稳定性的不同。

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