Maniglia C A, Loulakis P P, Sartorelli A C
J Natl Cancer Inst. 1986 Apr;76(4):739-44. doi: 10.1093/jnci/76.4.739.
The antithrombotic compound nafazatrom was evaluated in several in vivo and in vitro assays to elucidate the mechanism of its antimetastatic activity. C57BL/6 mice bearing B16 amelanotic subcutaneous tumors treated with 100 mg nafazatrom/kg/day exhibited a sixfold reduction in metastatic pulmonary lesions compared to lesion numbers in controls. The reduction in metastatic lesions was not accompanied by changes in primary tumor growth, and up to 1 microgram nafazatrom/ml did not inhibit tumor cell proliferation in vitro. Treatment of C57BL/6 mice with nafazatrom prior to iv inoculation of tumor cells failed to inhibit lung colony formation. In vitro exposure of exponentially growing B16 amelanotic cells to nafazatrom (1 microgram/ml for 72 hr) in culture did not change their ability to adhere to endothelial cell monolayers. B16 amelanotic cells degraded the matrix material of bovine endothelial cell monolayers; a heparin sulfate proteoglycan appeared to be the predominant matrix component released by these tumor cells, as judged by resistance to chondroitin ABC lyase and sensitivity to heparitinase and pronase degradation. Nafazatrom (1 microgram/ml for 72 hr) inhibited the solubilization of matrix components by approximately 60%. Tumor cell degradation of matrix components is an important event in the pathogenesis of metastasis. Thus the interference with this process appears to provide an explanation for the inhibition of malignant cell dissemination in vivo by nafazatrom.
对抗血栓化合物萘呋胺酯进行了多项体内和体外试验,以阐明其抗转移活性的机制。与对照组的转移病灶数量相比,接受100mg萘呋胺酯/kg/天治疗的携带B16无黑色素皮下肿瘤的C57BL/6小鼠的转移性肺病灶减少了六倍。转移病灶的减少并未伴随原发性肿瘤生长的变化,并且高达1μg/ml的萘呋胺酯在体外并未抑制肿瘤细胞增殖。在静脉接种肿瘤细胞之前用萘呋胺酯治疗C57BL/6小鼠未能抑制肺集落形成。在培养中将指数生长的B16无黑色素细胞体外暴露于萘呋胺酯(1μg/ml,持续72小时)并未改变其黏附于内皮细胞单层的能力。B16无黑色素细胞降解牛内皮细胞单层的基质材料;根据对软骨素ABC裂解酶的抗性以及对乙酰肝素酶和链霉蛋白酶降解的敏感性判断,硫酸乙酰肝素蛋白聚糖似乎是这些肿瘤细胞释放的主要基质成分。萘呋胺酯(1μg/ml,持续72小时)抑制基质成分的溶解约60%。肿瘤细胞对基质成分的降解是转移发病机制中的一个重要事件。因此,对这一过程的干扰似乎为萘呋胺酯在体内抑制恶性细胞扩散提供了解释。