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双(,-二乙基-4-甲基-4-哌嗪-1-甲酰胺)四-(异硫氰酸根合-κ)-钴(II),斯科特试验中产生蓝色的一种模型化合物。

Bis(,-diethyl-4-methyl-4-piperazine-1-carboxamide) tetra-kis-(iso-thio-cyanato-κ)-cobalt(II), a model compound for the blue color developed in the Scott test.

作者信息

Oliver Allen G, Lockwood Tracy-Lynn E, Zinna Jessica, Lieberman Marya

机构信息

Department of Chemistry and Biochemistry, University of Notre Dame, Notre Dame, IN 46556, USA.

出版信息

Acta Crystallogr E Crystallogr Commun. 2023 Feb 9;79(Pt 3):163-166. doi: 10.1107/S2056989023000981. eCollection 2023 Feb 1.

Abstract

The complex, bis-(,-diethyl-4-methyl-4-piperazine-1-carboxamide) tetra-kis(iso-thio-cyanato-κ)cobalt(II) (,-diethyl-4-methyl-4-piperazine-1-carboxamide = di-ethyl-carbamazine), (CHNO)[Co(NCS)], is presented. This com-plex is a blue precipitate, insoluble in water but soluble in organic solvents, that is formed from the reaction of diethylcarbamazine citrate, a protonated tertiary amine, with cobalt(II) and thio-cyanate. This reaction, in the form of the Scott test, is a common presumptive test for cocaine hydro-chloride. The known cobalt compound, [KCo(NCS)]·3HO, has a deep-blue coloration due to the tetra-hedral [Co(NCS)] that is also present in the ion pair with bulky amines, and is similar to the color of other tetra-hedral cobalt(II) complex ions, such as [CoCl]. The structure is consistent with a previous proposal that a hydro-phobic ion pair formed between [Co(NCS)] and two protonated mol-ecules of cocaine is responsible for the blue hydro-phobic products formed by cocaine in the Scott test.

摘要

介绍了配合物双(,-二乙基-4-甲基-4-哌嗪-1-甲酰胺)四(异硫氰酸根合-κ)钴(II)(,-二乙基-4-甲基-4-哌嗪-1-甲酰胺=二乙碳酰嗪),(CHNO)[Co(NCS)]。该配合物为蓝色沉淀,不溶于水但可溶于有机溶剂,它由柠檬酸二乙碳酰嗪(一种质子化叔胺)与钴(II)和硫氰酸盐反应形成。这种以斯科特试验形式进行的反应是检测盐酸可卡因的常见初步试验。已知的钴化合物[KCo(NCS)]·3HO由于四面体[Co(NCS)]而呈现深蓝色,该四面体也存在于与体积较大胺形成的离子对中,并且与其他四面体钴(II)络合离子如[CoCl]的颜色相似。该结构与先前的提议一致,即在斯科特试验中,[Co(NCS)]与两个质子化可卡因分子之间形成的疏水离子对是可卡因形成蓝色疏水产物的原因。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/dc78/9993914/6ae0349cd260/e-79-00163-fig1.jpg

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