Thakker D R, Boehlert C, Kirk K L, Antkowiak R, Creveling C R
J Biol Chem. 1986 Jan 5;261(1):178-84.
Selectivity of catechol O-methyltransferase has been examined for the three ring-fluorinated norepinephrines to elucidate the role of acidity of the phenolic groups in their methylation. Substitution of fluorine at the 5-position of norepinephrine reverses the selectivity of catechol O-methyltransferase so that p-O-methylation predominates. The 5-fluoro substituent also causes the pKa of the p-hydroxyl group to decrease substantially. In contrast, 2- and 6-fluoronorepinephrines are methylated predominantly at the m-hydroxyl group. These results suggest that acidity of a phenolic group can play an important role in its ability to be methylated by catechol O-methyltransferase. Percentages of p-O-methylation of norepinephrine and its fluorinated derivatives increase with pH. This relative increase in p-O-methylation appears to accompany ionization of a group with pKa of 8.6, 7.7, 7.9, and 8.4 for norepinephrine and its 2-, 5-, and 6-fluoro derivative, respectively. These pKa values are the same as or similar to the pKa values of a phenolic hydroxyl group of these substrates. 3,4-Dihydroxybenzyl alcohol and its 5-fluoro derivative are O-methylated by catechol O-methyltransferase to form p- and m-O-methyl products in approximately 1:1 and 4:1 ratios, respectively, at all pH values. Based on the above results, a catechol-binding site model for catechol O-methyltransferase is proposed in which the two phenolic hydroxyl groups of catechol substrates are postulated to be approximately equally spaced from the methyl group of the cosubstrate S-adenosylmethionine.
已对三种环氟化去甲肾上腺素的儿茶酚-O-甲基转移酶选择性进行了研究,以阐明酚羟基酸度在其甲基化过程中的作用。去甲肾上腺素5位的氟取代会逆转儿茶酚-O-甲基转移酶的选择性,从而使对位-O-甲基化占主导。5-氟取代基还会使对羟基的pKa大幅降低。相比之下,2-氟去甲肾上腺素和6-氟去甲肾上腺素主要在间羟基处甲基化。这些结果表明,酚羟基的酸度在其被儿茶酚-O-甲基转移酶甲基化的能力中可发挥重要作用。去甲肾上腺素及其氟化衍生物的对位-O-甲基化百分比随pH值升高而增加。这种对位-O-甲基化的相对增加似乎伴随着pKa分别为8.6、7.7、7.9和8.4的基团的电离,这些pKa值分别对应去甲肾上腺素及其2-、5-和6-氟衍生物。这些pKa值与这些底物酚羟基的pKa值相同或相似。在所有pH值下,3,4-二羟基苄醇及其5-氟衍生物被儿茶酚-O-甲基转移酶O-甲基化,分别以约1:1和4:1的比例形成对位和间位-O-甲基产物。基于上述结果,提出了一种儿茶酚-O-甲基转移酶的儿茶酚结合位点模型,其中假定儿茶酚底物的两个酚羟基与共底物S-腺苷甲硫氨酸的甲基大致等距。