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简单随机抽样中使用两个伴随变量的无回答情形下改进的指数型均值估计量

Improved exponential type mean estimators for non-response case using two concomitant variables in simple random sampling.

作者信息

Hussain Mujeeb, Zaman Qamruz, Khan Lakhkar, Metawa A E, Awwad Fuad A, Ismail Emad A A, Wasim Danish, Ahmad Hijaz

机构信息

Department of Statistics, University of Peshawar, Peshawar, Pakistan.

Department of Statistics, Government Post Graduate College Mardan, Pakistan.

出版信息

Heliyon. 2024 Mar 8;10(6):e27535. doi: 10.1016/j.heliyon.2024.e27535. eCollection 2024 Mar 30.

Abstract

This paper addresses new exponential estimators for population mean in case of non-response on both the study and the concomitant variables using simple random sampling. The expressions for theoretical bias and mean square error of new estimators are derived up to first-order approximation and comparisons are made with the existing estimators. The proposed estimators are observed more efficient as compared to the considered estimators in the literature. For instance, the classical [4] unbiased estimator, the estimator of [9], and other existing estimators under the explained conditions. The theoretical results are supported numerically by using real-life data sets, under the criteria of bias, mean square error, percent relative efficiency and mathematical conditions. It is also clear from the numerical results that the suggested exponential estimators performed better than the estimators in the literature.

摘要

本文讨论了在研究变量和伴随变量均存在无应答情况下,使用简单随机抽样对总体均值的新指数估计量。新估计量的理论偏差和均方误差表达式推导至一阶近似,并与现有估计量进行比较。结果表明,与文献中考虑的估计量相比,所提出的估计量更有效。例如,经典的[4]无偏估计量、[9]的估计量以及在所述条件下的其他现有估计量。通过使用实际数据集,在偏差、均方误差、相对效率百分比和数学条件的标准下,从数值上支持了理论结果。数值结果还清楚地表明,所建议的指数估计量比文献中的估计量表现更好。

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本文引用的文献

1
A new approach for estimating variance of a population employing information obtained from a stratified random sampling.
Heliyon. 2023 Nov 2;9(11):e21477. doi: 10.1016/j.heliyon.2023.e21477. eCollection 2023 Nov.
4
The problem of non-response in sample surveys.
J Am Stat Assoc. 1946 Dec;41(236):517-29. doi: 10.1080/01621459.1946.10501894.

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