rs2018736 纤维连接蛋白 5 多态性作为盆腔器官脱垂的决定因素：一项病例对照研究。
The rs2018736 fibulin-5 polymorphism as a determinant for pelvic organ prolapse: a case-control study.
机构信息
Division of Urogynecology and Reconstructive Pelvic Surgery, Department of Gynecology, Federal University of São Paulo, São Paulo, SP, Brazil.
Department of Internal Medicine, University of Utah, Salt Lake City, UT, USA.
出版信息
Climacteric. 2024 Jun;27(3):321-325. doi: 10.1080/13697137.2024.2327988. Epub 2024 Mar 27.
OBJECTIVE
Fibulin-5 is a connective tissue component and may play a role in pelvic organ prolapse (POP) pathogenesis. This study aimed to verify the association of the rs2018736 polymorphism of the fibulin-5 gene with POP in postmenopausal Brazilian women, and to determine the risk factors for POP.
METHOD
This observational, cross-sectional, case-control study assessed postmenopausal women with advanced POP (stages III and IV) and control women (stages 0 and I) by examination and peripheral blood sample collection. DNA sequences were analyzed by real-time reverse-transcriptase polymerase chain reaction. A logistic regression model was used with < 0.05 for significance.
RESULTS
A total of 565 participants were evaluated (325 POP and 240 control). The homozygous C allele of rs2018736 (CC) was protective against POP (odds ratio [OR] 0.49, 95% confidence interval [CI] 0.26-0.91). Age (OR 1.09, 95% CI 1.05-1.13), number of pregnancies (OR 1.14, 95% CI 1.01-1.28), vaginal delivery (OR 5.32, 95% CI 2.58-11.01), forceps delivery (OR 3.34, 95% CI 1.72-6.47), weight of newborn (OR 1.0007, 95% CI 1.0002-1.0011), family history of POP (OR 2.35, 95% CI 1.24-4.44), hypertension (OR 1.74, 95% CI 1.01-3.00) and diabetes (OR 2.19, 95% CI 1.07-4.48)] were independent predictors for POP; cesarean (OR 0.02, 95% CI 0.005-0.09) was protective.
CONCLUSION
The rs2018736-CC genotype of the fibulin-5 gene has a protective role against POP.
目的
纤连蛋白 5 是一种结缔组织成分，可能在盆腔器官脱垂（POP）发病机制中发挥作用。本研究旨在验证纤维连接蛋白 5 基因 rs2018736 多态性与绝经后巴西女性 POP 的关联，并确定 POP 的危险因素。
方法
本研究为观察性、横断面、病例对照研究，通过检查和外周血样采集评估患有晚期 POP（III 期和 IV 期）的绝经后女性和对照组女性（0 期和 I 期）。通过实时逆转录酶聚合酶链反应分析 DNA 序列。使用 logistic 回归模型，显著性水平为 < 0.05。
结果
共评估了 565 名参与者（325 名 POP 和 240 名对照组）。rs2018736 的纯合 C 等位基因（CC）对 POP 有保护作用（比值比 [OR] 0.49，95%置信区间 [CI] 0.26-0.91）。年龄（OR 1.09，95%CI 1.05-1.13）、妊娠次数（OR 1.14，95%CI 1.01-1.28）、阴道分娩（OR 5.32，95%CI 2.58-11.01）、产钳分娩（OR 3.34，95%CI 1.72-6.47）、新生儿体重（OR 1.0007，95%CI 1.0002-1.0011）、POP 家族史（OR 2.35，95%CI 1.24-4.44）、高血压（OR 1.74，95%CI 1.01-3.00）和糖尿病（OR 2.19，95%CI 1.07-4.48）是 POP 的独立预测因素；剖宫产（OR 0.02，95%CI 0.005-0.09）有保护作用。
结论
纤维连接蛋白 5 基因 rs2018736-CC 基因型对 POP 有保护作用。
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