Han Qingfang, Lin Beibei, Liu Ziwei, Li Mengsha, Luo Zhaopeng, Xie Xixian, Ma Lijuan, Su Hao, Sheng Xiang
College of Biotechnology, Tianjin University of Science and Technology, Tianjin, 300457, China.
Key Laboratory of Engineering Biology for Low-Carbon Manufacturing, Tianjin Institute of Industrial Biotechnology, Chinese Academy of Sciences, Tianjin, 300308, China.
ChemistryOpen. 2025 Jul;14(7):e202400433. doi: 10.1002/open.202400433. Epub 2025 Jan 7.
5-Enolpyruvylshikimate-3-phosphate synthase (EPSPS) catalyzes the conversion of 5-enolpyruvate (PEP) and shikimic acid phosphate (S3P) to 5-enolpyruvylshikimic acid-3-phosphate (EPSP), releasing inorganic phosphate. This reaction is the sixth step of the shikimate pathway, which is a metabolic pathway used by microorganisms and plants for the biosynthesis of aromatic amino acids and folates but not in mammals. In the present study, the detailed reaction mechanism of EPSPS from Nicotiana tabacum (NtEPSPS) is revealed by quantum chemical calculations with the cluster approach. The reaction is proposed to involve the formation of a carbocation intermediate, the formation of a tetrahedral intermediate, the C-O bond cleavage and the re-formation of C=C bond. All four steps are concerted processes involving proton transfer events. The calculations suggest a step-wise mechanism for the formation of the tetrahedral intermediate by the proton transfer from the hydroxyl group of S3P to Asp331 and the nucleophilic attack of hydroxyl group on the carbocation, which is consistent with the proposal in literature. The energy profile for the entire reaction is presented, showing that C-O bond cleavage of the tetrahedral intermediate, releasing phosphate, is the rate-limiting step. The interaction between the Glu359 residue and the phosphate group is significant in stabilizing the phosphate.
5-烯醇丙酮酸莽草酸-3-磷酸合酶(EPSPS)催化5-烯醇丙酮酸(PEP)和磷酸莽草酸(S3P)转化为5-烯醇丙酮酸莽草酸-3-磷酸(EPSP),并释放无机磷酸。该反应是莽草酸途径的第六步,莽草酸途径是微生物和植物用于生物合成芳香族氨基酸和叶酸的代谢途径,但哺乳动物中不存在此途径。在本研究中,采用簇方法通过量子化学计算揭示了烟草(NtEPSPS)中EPSPS的详细反应机理。该反应被认为涉及碳正离子中间体的形成、四面体中间体的形成、C-O键的断裂以及C=C键的重新形成。所有这四个步骤都是涉及质子转移事件的协同过程。计算结果表明,通过从S3P的羟基向Asp331进行质子转移以及羟基对碳正离子的亲核攻击,形成四面体中间体的机理是分步进行的,这与文献中的提议一致。给出了整个反应的能量分布,表明四面体中间体的C-O键断裂并释放磷酸是限速步骤。Glu359残基与磷酸基团之间的相互作用在稳定磷酸方面具有重要意义。