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氯形成氯仿的机制及其被二氧化氯抑制的情况。

Mechanism of chloroform formation by chlorine and its inhibition by chlorine dioxide.

作者信息

Suh D H, Abdel-Rahman M S

出版信息

Fundam Appl Toxicol. 1985 Apr;5(2):305-13. doi: 10.1016/0272-0590(85)90078-8.

Abstract

Chlorination of drinking waters leads to the formation of trihalomethanes arising from the reaction of chlorine and organic substances. Therefore, chlorine dioxide (ClO2) which does not produce trihalomethanes is being considered as an alternative disinfectant. It has been reported that rat blood chloroform levels were significantly decreased after treatment with ClO2. Studies were conducted to investigate the mechanisms of chloroform formation by chlorine (HOCl) and its inhibition by ClO2 (5 mg/liter) in the presence of HOCl (5, 10, 20 mg/liter) using sodium citrate (1 mM) as an organic substance. When citrate was reacted with HOCl, beta-ketoglutaric acid, monochloroacetone, dichloroacetone, and trichloroacetone were produced as reaction intermediates and chloroform as a final product. There was a linear relationship between the concentrations of HOCl and the formation of chloroform. When ClO2 was substituted for HOCl, neither chloroform was formed nor citrate concentration was changed. Further, chloroform formation was inhibited by ClO2 in the presence of HOCl and citrate and the degree of inhibition depends on the ratio of ClO2/HOCl. Gas chromatograph/mass spectrometer analysis indicates that this inhibition is related to the reaction of ClO2 with beta-ketoglutaric acid to form malonic acid. Chlorine dioxide also oxidizes other intermediates such as monochloroacetone and dichloroacetone to acetic acid. These studies indicate that ClO2 inhibits chloroform formation from citrate and HOCl by the oxidation of the intermediates which were involved in the reaction of chloroform formation.

摘要

饮用水氯化会导致氯与有机物质反应生成三卤甲烷。因此,不会产生三卤甲烷的二氧化氯(ClO₂)正被视为一种替代消毒剂。据报道,用ClO₂处理后大鼠血液中的氯仿水平显著降低。开展了研究,以探讨在以柠檬酸钠(1 mM)作为有机物质的情况下,氯(HOCl)形成氯仿的机制以及ClO₂(5毫克/升)在HOCl(5、10、20毫克/升)存在时对其的抑制作用。当柠檬酸盐与HOCl反应时,会生成β-酮戊二酸、一氯丙酮、二氯丙酮和三氯丙酮作为反应中间体,并生成氯仿作为最终产物。HOCl的浓度与氯仿的形成之间存在线性关系。当用ClO₂替代HOCl时,既不会形成氯仿,柠檬酸盐浓度也不会改变。此外,在HOCl和柠檬酸盐存在的情况下,ClO₂会抑制氯仿的形成,抑制程度取决于ClO₂/HOCl的比例。气相色谱/质谱分析表明,这种抑制作用与ClO₂与β-酮戊二酸反应形成丙二酸有关。二氧化氯还会将其他中间体(如一氯丙酮和二氯丙酮)氧化为乙酸。这些研究表明,ClO₂通过氧化参与氯仿形成反应的中间体来抑制柠檬酸盐和HOCl形成氯仿。

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