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溴化乙锭与左手螺旋(Z型)DNA结合会在嵌入位点产生右手螺旋DNA区域。

Ethidium binding to left-handed (Z) DNAs results in regions of right-handed DNA at the intercalation site.

作者信息

Walker G T, Stone M P, Krugh T R

出版信息

Biochemistry. 1985 Dec 3;24(25):7462-71. doi: 10.1021/bi00346a065.

Abstract

The equilibrium binding of ethidium to the right-handed (B) and left-handed (Z) forms of poly(dG-dC).poly(dG-dC) and poly(dG-m5dC).poly(dG-m5dC) was investigated by optical and phase partition techniques. Ethidium binds to the polynucleotides in a noncooperative manner under B-form conditions, in sharp contrast to highly cooperative binding under Z-form conditions. Correlation of binding isotherms with circular dichroism (CD) data indicates that the cooperative binding of ethidium under Z-form conditions is associated with a sequential conversion of the polymer from a left-handed to a right-handed conformation. Determination of bound drug concentrations by various titration techniques and the measurement of circular dichroism spectra have enabled us to calculate the number of base pairs of left-handed DNA that adopt a right-handed conformation for each bound drug; 3-4 base pairs of left-handed poly(dG-dC).poly(dG-dC) in 4.4 M NaCl switch to the right-handed form for each bound ethidium, while approximately 25 and 7 base pairs switch conformations for each bound ethidium in complexes with poly(dG-dC).poly(dG-dC) in 40 microM [Co(NH3)6]Cl3 and poly(dG-m5dC).poly(dG-m5dC) in 2 mM MgCl2, respectively. The induced ellipticity at 320 nm for the ethidium-poly(dG-dC).poly(dG-dC) complex in 4.4 M NaCl indicates that the right-handed regions are nearly saturated with ethidium even though the overall level of saturation is very low. The circular dichroism data indicate that ethidium intercalates to form a right-handed-bound drug region, even at low r values where the CD spectra show that the majority of the polymer is in a left-handed conformation.

摘要

通过光学和相分配技术研究了溴化乙锭与聚(dG-dC)·聚(dG-dC)和聚(dG-m5dC)·聚(dG-m5dC)的右手(B)型和左手(Z)型的平衡结合。在B型条件下,溴化乙锭以非协同方式与多核苷酸结合,这与在Z型条件下的高度协同结合形成鲜明对比。结合等温线与圆二色性(CD)数据的相关性表明,在Z型条件下溴化乙锭的协同结合与聚合物从左手构象到右手构象的顺序转变有关。通过各种滴定技术测定结合药物浓度并测量圆二色性光谱,使我们能够计算出每个结合药物采用右手构象的左手DNA碱基对数量;在4.4 M NaCl中,每结合一个溴化乙锭,4个左手聚(dG-dC)·聚(dG-dC)碱基对转变为右手形式,而在40 μM [Co(NH3)6]Cl3中的聚(dG-dC)·聚(dG-dC)复合物以及在2 mM MgCl2中的聚(dG-m5dC)·聚(dG-m5dC)复合物中,每结合一个溴化乙锭,分别约有25个和7个碱基对转变构象。在4.4 M NaCl中,溴化乙锭-聚(dG-dC)·聚(dG-dC)复合物在320 nm处的诱导椭圆率表明,即使总体饱和度水平非常低,右手区域也几乎被溴化乙锭饱和。圆二色性数据表明,即使在CD光谱显示大多数聚合物处于左手构象的低r值下,溴化乙锭也会插入形成右手结合的药物区域。

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