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非洲爪蟾(达丁)牙齿发育和替换的时间尺度。

The time scale of tooth development and replacement in Xenopus laevis (Daudin).

作者信息

Shaw J P

出版信息

J Anat. 1979 Sep;129(Pt 2):323-42.

Abstract

One hundred and seventy two larval specimens of Xenopus laevis were reared in such a way that their rates of development (as measured by external criteria) were similar, and so the course of dental development could be examined histologically in a cross sectional study. In this way the events of tooth development were observed, and a time scale constructed for these events. The teeth took an average time of 26 days to develop, erupt and become ankylosed to the bony pedestal, after which each tooth was in a functional position for only about 7 days. Individual tooth replacement was assessed to occur about every 16 days. By comparing the number and size of the odontoblasts responsible for dentinogenesis in 18 months old adult Xenopus laevis with the odontoblasts in the larval specimens, the conclusion was drawn that, despite the larger size of the adult teeth, the time involved in their development and replacement may well be of similar duration to the smaller larval teeth. The significance of the findings for the Zahnreihen Theory is discussed.

摘要

172只非洲爪蟾幼体标本的饲养方式,使得它们的发育速度(通过外部标准衡量)相似,这样就可以在横断面研究中通过组织学方法检查牙齿发育过程。通过这种方式观察了牙齿发育事件,并为这些事件构建了一个时间尺度。牙齿发育、萌出并与骨基座融合平均需要26天,之后每颗牙齿仅在功能位置约7天。个体牙齿替换评估为大约每16天发生一次。通过比较18个月大的成年非洲爪蟾中负责牙本质形成的成牙本质细胞的数量和大小与幼体标本中的成牙本质细胞,得出的结论是,尽管成年牙齿更大,但它们发育和替换所涉及的时间很可能与较小的幼体牙齿相似。讨论了这些发现对牙列理论的意义。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/21ae/1233050/7e37ce04dc45/janat00238-0100-a.jpg

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