Suppr超能文献

非洲爪蟾5S DNA的纯化及某些特性

Purification and some characteristics of 5S DNA from Xenopus laevis.

作者信息

Brown D D, Wensink P C, Jordan E

出版信息

Proc Natl Acad Sci U S A. 1971 Dec;68(12):3175-9. doi: 10.1073/pnas.68.12.3175.

Abstract

DNA containing the multiple genes for 5S RNA has been isolated from the genome of Xenopus laevis. Whereas 5S RNA is about 57% G + C, the 5S DNA has a base composition of about 33-35% GC and consists of two alternating regions that differ in base composition by at least 20% GC. A denaturation map of 5S DNA analyzed by electron microscopy demonstrates that the repeating pattern is regular and each repeating unit has a mass of about 500,000 daltons. If one gene for 5S RNA (84,000 daltons native) were present in each repeat, it should comprise about 16.8% of 5S DNA. This arrangement is confirmed, since 6.8% of pure 5S DNA (13.6% of its base pairs) hybridized with 5S RNA. The remaining 83% of each repeating unit is considered to be "spacer" DNA. The 5S RNA hybridizes with about 0.05% of the bulk DNA of X. laevis, so that 5S DNA comprises about 0.7% of the total nuclear DNA. This is equivalent to about 24,000 repeating units for each haploid complement of DNA. These repeats are highly clustered; as many as 86 have been visualized along a single DNA molecule.

摘要

已从非洲爪蟾的基因组中分离出含有5S RNA多个基因的DNA。5S RNA约含57%的鸟嘌呤和胞嘧啶(G + C),而5S DNA的碱基组成约为33 - 35%的GC,由两个交替区域组成,其碱基组成的GC含量差异至少为20%。通过电子显微镜分析的5S DNA变性图谱表明,重复模式是规则的,每个重复单元的质量约为500,000道尔顿。如果每个重复单元中存在一个5S RNA基因(天然状态下为84,000道尔顿),它应占5S DNA的约16.8%。这种排列得到了证实,因为6.8%的纯5S DNA(其碱基对的13.6%)与5S RNA杂交。每个重复单元的其余83%被认为是“间隔”DNA。5S RNA与非洲爪蟾约0.05%的总DNA杂交,因此5S DNA占总核DNA的约0.7%。这相当于每个单倍体DNA互补体约有24,000个重复单元。这些重复序列高度聚集;在单个DNA分子上已观察到多达86个。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/baa6/389616/4eae7ff0ca41/pnas00087-0281-a.jpg

文献AI研究员

20分钟写一篇综述,助力文献阅读效率提升50倍。

立即体验

用中文搜PubMed

大模型驱动的PubMed中文搜索引擎

马上搜索

文档翻译

学术文献翻译模型,支持多种主流文档格式。

立即体验