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补体蛋白C5b - 8产生的跨膜通道的大小。

Size of the transmembrane channels produced by complement proteins C5b-8.

作者信息

Ramm L E, Whitlow M B, Mayer M M

出版信息

J Immunol. 1982 Sep;129(3):1143-6.

PMID:6286757
Abstract

It has been shown previously that erythrocytes can be lysed by complement proteins C5b-8, albeit at a much lower rate than C5b-9. We have now performed kinetic sieving experiments with resealed erythrocyte ghosts using sucrose (0.9 nm molecular diameter) and inulin (3.0 nm molecular diameter) as markers. We found that treatment of the ghosts with C5b-8 released sucrose, but not inulin. Addition of C9 to ghosts carrying C5b-8 dramatically increased the rate of sucrose flux and, in addition, caused release of inulin. Hence, unlike C5b-9 channels, those formed by C5b-8 measure less than 3 nm in diameter. Formation of C5b-8 channels was very slow compared with that of C5b-9 channels. Also, we found that about two-thirds of the C5b-8 ghosts did not have sucrose-releasing channels, but such channels were formed on reaction with C9.

摘要

先前已经表明,红细胞可被补体蛋白C5b - 8裂解,尽管其速率比C5b - 9低得多。我们现在使用蔗糖(分子直径0.9纳米)和菊粉(分子直径3.0纳米)作为标记物,对重新封闭的红细胞血影进行了动力学筛分实验。我们发现,用C5b - 8处理血影会释放蔗糖,但不会释放菊粉。向携带C5b - 8的血影中添加C9会显著提高蔗糖通量速率,此外,还会导致菊粉释放。因此,与C5b - 9通道不同,由C5b - 8形成的通道直径小于3纳米。与C5b - 9通道相比,C5b - 8通道的形成非常缓慢。此外,我们发现约三分之二的C5b - 8血影没有蔗糖释放通道,但与C9反应时会形成此类通道。

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