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在无HCO₃⁻情况下降低pH对牛蛙胃窦异常和正常电位反应的影响

Effect of reduced pH in absence of HCO3(-) on anomalous and normal potential responses in bullfrog antrum.

作者信息

Schwartz M, Carrasquer G, Rehm W S

出版信息

Biochim Biophys Acta. 1984 Jun 27;773(2):189-96. doi: 10.1016/0005-2736(84)90082-8.

DOI:10.1016/0005-2736(84)90082-8
PMID:6329282
Abstract

Effect of changing [K+], [Na+] and [Cl-] in nutrient solution on potential difference (PD) and resistance was studied in bullfrog antrum with and without nutrient HCO3(-) but with 95% O2/5% CO2 in both cases. In both cases, changing from 4 to 40 mM K+ gave about the same initial PD maximum (anomalous response) which was followed by a decrease below control level. Latter effect was much less with zero than with 25 mM HCO3(-). Changing from 102 to 8 mM Na+ gave initial normal PD response about the same in both cases. However, 10 min later the change in PD with zero HCO3(-) was insignificant but with 25 mM HCO3(-) the PD decreased (anomalous response of electrogenic NaCl symport). PD maxima due to K+ and Na+ were largely related to (Na+ + K+)-ATPase pump. Changes in nutrient Cl- from 81 to 8.1 mM gave only a decrease in PD (normal response). Initial PD increases are explained by relative increases in resistance of simple conductance pathways and of parallel pathways of (Na+ + K+)-ATPase pump and Na+/Cl- symport. Removal of HCO3(-) and concurrent reduction of pH modify resistance of these pathways.

摘要

在有和没有营养液 HCO₃⁻的情况下,研究了营养液中[K⁺]、[Na⁺]和[Cl⁻]的变化对牛蛙胃窦电位差(PD)和电阻的影响,两种情况下均通入 95% O₂/5% CO₂。在这两种情况下,将 K⁺浓度从 4 mM 变为 40 mM 时,最初的 PD 最大值大致相同(反常反应),随后降至对照水平以下。与 25 mM HCO₃⁻相比,零 HCO₃⁻时后一种效应要小得多。将 Na⁺浓度从 102 mM 变为 8 mM 时,两种情况下最初的正常 PD 反应大致相同。然而,10 分钟后,零 HCO₃⁻时 PD 的变化不显著,但 25 mM HCO₃⁻时 PD 降低(电中性 NaCl 同向转运体的反常反应)。由 K⁺和 Na⁺引起的 PD 最大值在很大程度上与(Na⁺ + K⁺)-ATP 酶泵有关。营养液中 Cl⁻浓度从 81 mM 变为 8.1 mM 时,仅使 PD 降低(正常反应)。最初的 PD 增加可以通过简单传导途径以及(Na⁺ + K⁺)-ATP 酶泵和 Na⁺/Cl⁻同向转运体的平行途径电阻的相对增加来解释。去除 HCO₃⁻并同时降低 pH 会改变这些途径的电阻。

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