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抗肿瘤药物9-羟基玫瑰树碱及其衍生物的自动氧化。

Autoxidation of the antitumor drug 9-hydroxyellipticine and its derivatives.

作者信息

Auclair C, Hyland K, Paoletti C

出版信息

J Med Chem. 1983 Oct;26(10):1438-44. doi: 10.1021/jm00364a015.

Abstract

In aqueous solution and using molecular oxygen as electron acceptor, the antitumor drug 9-hydroxyellipticine (9-OH-E) undergoes a spontaneous oxidation to give hydrogen peroxide (H2O2), the quinone imine 9-oxoellipticine (9-oxo-E), and a dimer of 9-OH-E(9-OH-E2). Electron paramagnetic resonance (EPR) experiments performed either in alkaline Me2SO or in phosphate buffer in the presence of the spin trap 5,5-dimethylpyrroline 1-oxide (DMPO) suggest that the oxidation process involves the initial formation of superoxide anion (O2- .) and the free radical of the drug. In aqueous medium, this step is followed by the dismutation of both O2- . and free radicals of the drug generating, respectively, H2O2 and 9-oxo-E. 9-Oxo-E further reacts with the 9-OH-E remaining in the solution to form the dimer 9-OH-E2 as the terminal product. The autoxidation process is strongly enhanced by superoxide dismutase and manganese ions. In the ellipticine series, all drugs that have an OH group in position 9 exhibit the ability to transfer one electron on molecular oxygen to generate O2- .. This property may be involved in the cytotoxic activities of these drugs.

摘要

在水溶液中并以分子氧作为电子受体时,抗肿瘤药物9-羟基玫瑰树碱(9-OH-E)会发生自发氧化,生成过氧化氢(H2O2)、醌亚胺9-氧代玫瑰树碱(9-氧代-E)以及9-OH-E的二聚体(9-OH-E2)。在碱性二甲基亚砜中或在存在自旋捕捉剂5,5-二甲基吡咯啉1-氧化物(DMPO)的磷酸盐缓冲液中进行的电子顺磁共振(EPR)实验表明,氧化过程涉及超氧阴离子(O2-·)和药物自由基的初始形成。在水性介质中,此步骤之后是O2-·和药物自由基的歧化反应,分别生成H2O2和9-氧代-E。9-氧代-E进一步与溶液中剩余的9-OH-E反应,形成二聚体9-OH-E2作为最终产物。超氧化物歧化酶和锰离子会强烈增强自氧化过程。在玫瑰树碱系列中,所有在9位具有羟基的药物都表现出将一个电子转移到分子氧上以生成O2-·的能力。此特性可能与这些药物的细胞毒性活性有关。

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