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心脏钠钙交换系统的化学计量学。

The stoichiometry of the cardiac sodium-calcium exchange system.

作者信息

Reeves J P, Hale C C

出版信息

J Biol Chem. 1984 Jun 25;259(12):7733-9.

PMID:6736024
Abstract

A thermodynamic approach was adopted for determining the stoichiometry of the cardiac Na-Ca exchange system. Vesicles were equilibrated with 0.1 mM 45CaCl2 in a medium containing 30 mM NaCl, 20 mM KCl, and 110 mM LiCl. The vesicles were then treated with valinomycin and diluted into media containing the same 45CaCl2 and NaCl concentrations as in the equilibration medium but with the external KCl concentration adjusted so as to impose either positive or negative membrane potentials (delta psi). 45Ca2+ uptake ensued upon establishing a positive (inside) potential whereas 45Ca2+ efflux was observed for a negative delta psi. These delta psi-dependent Ca2+ movements did not occur if NaCl was omitted from the media, indicating that they were mediated by the Na-Ca exchanger. High concentrations of either NaCl or CaCl2 inhibited the delta psi-dependent Ca2+ movements. To determine the exchange stoichiometry, a series of Na+ gradients were established across the vesicle membrane so as to oppose the effects of a constant delta psi (either positive or negative) on Ca2+ movements. The stoichiometry n could be determined from the magnitude of the Na+ gradient that exactly compensated for delta psi such that no net Ca2+ movement occurred. This point is defined by the relation (n - 2)delta psi = nENa where ENa is the equilibrium potential for Na+ under these conditions. The value of n (+/- S.E.) determined in this way was 2.97 +/- 0.03 (n = 9).

摘要

采用热力学方法来确定心脏钠钙交换系统的化学计量。囊泡在含有30 mM氯化钠、20 mM氯化钾和110 mM氯化锂的培养基中与0.1 mM氯化钙达到平衡。然后用缬氨霉素处理囊泡,并稀释到含有与平衡培养基中相同氯化钙和氯化钠浓度的培养基中,但外部氯化钾浓度经过调整以施加正或负膜电位(δψ)。建立正(内)电位时会发生钙离子摄取,而负的δψ则会观察到钙离子外流。如果培养基中省略氯化钠,则不会发生这些依赖于δψ的钙离子移动,这表明它们是由钠钙交换体介导的。高浓度的氯化钠或氯化钙会抑制依赖于δψ的钙离子移动。为了确定交换化学计量,在囊泡膜上建立了一系列钠梯度,以对抗恒定δψ(正或负)对钙离子移动的影响。化学计量n可以从恰好补偿δψ从而不发生净钙离子移动的钠梯度大小来确定。这一点由关系式(n - 2)δψ = nENa定义,其中ENa是在这些条件下钠的平衡电位。以这种方式确定的n(±标准误差)值为2.97±0.03(n = 9)。

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