Dwulet F E, Putnam F W
Proc Natl Acad Sci U S A. 1981 Feb;78(2):790-4. doi: 10.1073/pnas.78.2.790.
The complete amino acid sequence has been determined for a 50,000-dalton fragment that is an internal segment of the single polypeptide chain of human ceruloplasmin [ferroxidase; iron(II):oxygen oxidoreductase, EC 1.16.3.1]. The fragment (designated Cp F4) contains 405 amino acid residues, has one glucosamine-containing carbohydrate unit, and, together with the 19,000-dalton fragment that follows it, accounts for the carboxyl-terminal half of the molecule. Fragment Cp F4 has a very nonuniform distribution of certain amino acid residues, which show a high potential to be adjacent to or one residue separated from a similar amino acid. This is most pronounced for acid and amide residues (65% clustered), aromatic residues (56% clustered), and basic residues (41% clustered). In addition, there is a long-range clustering of proline residues at the amino- and carboxyl-terminal 60 residues (50% clustered). Also, there are a number of short repeated segments of sequence. Calculations based on parameters predictive of secondary structure folding patterns indicate that the 50,000-dalton fragment has a low content of alpha-helix and is predominantly beta-sheet, beta-turn, and random in structure. Limited enzymatic cleavage of human ceruloplasmin to yield 67,000-, 50,000-, and 19,000-dalton fragments occurs at specific exposed sites of random structure in between domain-like regions.
已确定一种50000道尔顿片段的完整氨基酸序列,该片段是人类铜蓝蛋白[铁氧化酶;铁(II):氧氧化还原酶,EC 1.16.3.1]单条多肽链的内部片段。该片段(命名为Cp F4)含有405个氨基酸残基,有一个含氨基葡萄糖的碳水化合物单元,并且与紧随其后的19000道尔顿片段一起,构成了该分子的羧基末端一半。片段Cp F4中某些氨基酸残基的分布非常不均匀,这些残基显示出与相似氨基酸相邻或相隔一个残基的高可能性。这在酸性和酰胺残基(65%成簇)、芳香族残基(56%成簇)和碱性残基(41%成簇)中最为明显。此外,在氨基末端和羧基末端的60个残基处脯氨酸残基存在长程成簇现象(50%成簇)。而且,还有一些短的重复序列片段。基于预测二级结构折叠模式的参数进行的计算表明,50000道尔顿片段的α-螺旋含量较低,主要结构为β-折叠、β-转角和无规结构。人类铜蓝蛋白经有限酶切产生67000道尔顿、50000道尔顿和19000道尔顿片段,这发生在类似结构域区域之间随机结构的特定暴露位点。