Hunt J, Massey V
Department of Biological Chemistry, University of Michigan, Ann Arbor 48109-0606.
J Biol Chem. 1994 Jul 22;269(29):18904-14.
The reductive half-reaction of milk xanthine dehydrogenase (XDH) with NADH and with xanthine has been studied at pH 7.5, 25 degree C. NADH reduces XDH to the two-electron reduced form at a rate of 18 s-1, independent of NADH concentration over the range studied. Further reduction by NADH to the four-electron state is inhibited by excess NADH. Subsequent binding of NADH to the four-electron reduced form of the enzyme causes the redistribution of one electron from the flavin to the molybdenum center. The four-electron reduced species reached through reduction by NADH is the same as the species obtained upon reaction of NAD with fully reduced XDH. In contrast, xanthine rapidly reduces XDH to the four-electron level; further reduction is comparatively slow and is inhibited by excess xanthine. Studies using substoichiometric xanthine show that the reaction of XDH with 1 equivalent of xanthine involves rapid substrate binding and rapid reduction of the molybdenum center of the enzyme. Before the release of urate from the molybdenum active site, an electron is transferred at 15 s-1 from the reduced molybdenum center to one of the iron-sulfur centers of XDH. Urate is then released at a rate of 13 s-1, followed by a rapid electron redistribution within the protein. The reductive half-reaction of XDH with xanthine is rate-limiting in xanthine/NAD turnover, which appears to occur between the two- and four-electron reduced enzyme species. The reduction of XDH by substoichiometric amounts of the fluorescent substrate xanthopterin was also studied. This reaction, monitored by changes in both absorbance and fluorescence, was found to involve the formation of two molybdenum complexes (an Eox.S complex and an Ered.P complex) followed by the release of the product, leucopterin.
在pH 7.5、25℃条件下,研究了牛奶黄嘌呤脱氢酶(XDH)与NADH以及与黄嘌呤的还原半反应。NADH以18 s⁻¹的速率将XDH还原为双电子还原形式,在所研究的浓度范围内,该速率与NADH浓度无关。过量的NADH会抑制NADH进一步将其还原为四电子状态。随后NADH与酶的四电子还原形式结合,导致一个电子从黄素重新分布到钼中心。通过NADH还原得到的四电子还原物种与NAD与完全还原的XDH反应得到的物种相同。相比之下,黄嘌呤能迅速将XDH还原到四电子水平;进一步还原相对较慢,且会被过量的黄嘌呤抑制。使用亚化学计量的黄嘌呤进行的研究表明,XDH与1当量黄嘌呤的反应涉及底物的快速结合以及酶钼中心的快速还原。在尿酸从钼活性位点释放之前,一个电子以15 s⁻¹的速率从还原的钼中心转移到XDH的一个铁硫中心。然后尿酸以13 s⁻¹的速率释放,随后蛋白质内部迅速发生电子重新分布。XDH与黄嘌呤的还原半反应在黄嘌呤/NAD周转中是限速步骤,该周转似乎发生在双电子和四电子还原的酶物种之间。还研究了亚化学计量的荧光底物黄蝶呤对XDH的还原作用。通过吸光度和荧光变化监测该反应,发现其涉及形成两种钼配合物(一种Eox.S配合物和一种Ered.P配合物),随后释放产物白蝶呤。