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由Cu2+介导的糖化胰岛素中组氨酸残基的位点特异性氧化。

Site-specific oxidation of histidine residues in glycated insulin mediated by Cu2+.

作者信息

Cheng R Z, Kawakishi S

机构信息

Department of Food Science and Technology, Nagoya University, Japan.

出版信息

Eur J Biochem. 1994 Aug 1;223(3):759-64. doi: 10.1111/j.1432-1033.1994.tb19050.x.

Abstract

The site-specific oxidation of histidine residues in glycated insulin mediated by copper ions and the relationship between the oxidation sites and the steric conformation of insulin are discussed in this study. Glycated insulin was prepared by incubating native insulin with glucose in 67 mM sodium phosphate, pH 7.5, at 37 degrees C for 30 h. In the presence of micromolar concentrations of Cu2+, glycated insulin was oxidized and its fragmentation or aggregation was detected. Accompanying the fragmentation, new N-termini were generated. The residues in these N-termini were identified as alanine, proline, valine, leucine and isoleucine by comparing dansyl derivatives with standard dansyl-amino acid products. Furthermore, several oxidized products of glycated insulin were isolated using reverse-phase HPLC (P1-P3). From amino acid composition and sequence analyses, it was determined that His10 on the insulin B-chain was modified in each of these peptides, while His5 was also modified in P3. The difference in susceptibility of His10 and His5 to oxidative modification is considered to be due to easier coordination of Cu2+ with His10, which further forms a complex with the Amadori compound at B-chain Phe1 that is vicinal to His10 in the steric conformation of insulin. This complex may generate an active oxygen species, which induces the degradation of the imidazole ring at His10, leading to aggregation or fragmentation of insulin.

摘要

本研究探讨了铜离子介导的糖化胰岛素中组氨酸残基的位点特异性氧化,以及氧化位点与胰岛素空间构象之间的关系。通过将天然胰岛素与葡萄糖在67 mM磷酸钠(pH 7.5)中于37℃孵育30小时制备糖化胰岛素。在微摩尔浓度的Cu2+存在下,糖化胰岛素被氧化,并检测到其片段化或聚集。伴随着片段化,产生了新的N末端。通过将丹磺酰衍生物与标准丹磺酰氨基酸产物进行比较,确定这些N末端中的残基为丙氨酸、脯氨酸、缬氨酸、亮氨酸和异亮氨酸。此外,使用反相高效液相色谱法(P1-P3)分离了几种糖化胰岛素的氧化产物。通过氨基酸组成和序列分析确定,胰岛素B链上的His10在这些肽中的每一个中都被修饰,而His5在P3中也被修饰。His10和His5对氧化修饰敏感性的差异被认为是由于Cu2+与His10更容易配位,这进一步与胰岛素空间构象中与His10相邻的B链Phe1处的阿马多里化合物形成复合物。这种复合物可能产生活性氧,诱导His10处咪唑环的降解,导致胰岛素的聚集或片段化。

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