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前列腺素H合酶的环氧化酶与过氧化物酶活性之间的密切关系。阿魏酸的过氧化物酶反应及其对花生四烯酸反应的影响。

Intimate relation between cyclooxygenase and peroxidase activities of prostaglandin H synthase. Peroxidase reaction of ferulic acid and its influence on the reaction of arachidonic acid.

作者信息

Bakovic M, Dunford H B

机构信息

Department of Chemistry, University of Alberta, Edmonton, Canada.

出版信息

Biochemistry. 1994 May 31;33(21):6475-82. doi: 10.1021/bi00187a013.

Abstract

The oxidation of ferulic acid by hydrogen peroxide catalyzed by prostaglandin H synthase follows a modified ping-pong irreversible mechanism, as is the case for classical peroxidases. The rate constant for the reaction of prostaglandin H synthase with hydrogen peroxide, determined from steady-state results, is (1.31 +/- 0.1) x 10(6) M-1 s-1, and for the reaction of prostaglandin H synthase-compound II with ferulic acid it is (5.5 +/- 0.3) x 10(6) M-1 s-1. Cyclooxygenase and peroxidase functions of prostaglandin H synthase were studied by comparing the initial rates of reaction of the cyclooxygenase substrate, arachidonic acid, and a peroxidase reducing substrate, ferulic acid, in mixtures of the two substrates. For both an equimolar ratio of arachidonic and ferulic acids and ferulic acid in excess of arachidonic acid a stimulation of the cyclooxygenase reaction is observed. The concentration of ferulic acid necessary to produce 50% stimulation of 0.2 mM arachidonic acid oxidation is 0.14 +/- 0.02 mM. A striking feature of our results is that prostaglandin H synthase catalyzes oxidation of the two substrates in a constant and fixed molar ratio of ferulic acid to arachidonic acid of 2:1, despite widely different starting concentrations. If arachidonic acid is in excess of ferulic acid, enzyme inactivation occurs. The results can be explained by an interconnected cyclooxygenase-peroxidase unbranched free radical mechanism in which arachidonic acid reacts with either the ferryl oxygen or the porphyrin pi-cation radical part of a conventional peroxidase compound I (a FeIV = O porphyrin pi-cation radical) and ferulic acid reacts with compound II (FeIV = O).(ABSTRACT TRUNCATED AT 250 WORDS)

摘要

前列腺素H合酶催化过氧化氢氧化阿魏酸遵循一种修正的乒乓不可逆机制,这与经典过氧化物酶的情况相同。根据稳态结果确定,前列腺素H合酶与过氧化氢反应的速率常数为(1.31±0.1)×10⁶ M⁻¹ s⁻¹,而前列腺素H合酶-化合物II与阿魏酸反应的速率常数为(5.5±0.3)×10⁶ M⁻¹ s⁻¹。通过比较两种底物混合物中环氧化酶底物花生四烯酸和过氧化物酶还原底物阿魏酸的初始反应速率,研究了前列腺素H合酶的环氧化酶和过氧化物酶功能。对于花生四烯酸和阿魏酸等摩尔比以及阿魏酸过量于花生四烯酸的情况,均观察到环氧化酶反应受到刺激。产生50%刺激0.2 mM花生四烯酸氧化所需的阿魏酸浓度为0.14±0.02 mM。我们结果的一个显著特征是,尽管起始浓度差异很大,但前列腺素H合酶以阿魏酸与花生四烯酸2:1的恒定固定摩尔比催化两种底物的氧化。如果花生四烯酸过量于阿魏酸,酶会失活。这些结果可以通过一种相互关联的环氧化酶-过氧化物酶无分支自由基机制来解释,其中花生四烯酸与传统过氧化物酶化合物I(FeIV = O卟啉π-阳离子自由基)的铁氧或卟啉π-阳离子自由基部分反应,而阿魏酸与化合物II(FeIV = O)反应。(摘要截至于250字)

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