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在可控芬顿反应中,取决于活性氧物种的花青染料的特征性漂白曲线。

Characteristic bleaching profiles of cyanine dyes depending on active oxygen species in the controlled Fenton reaction.

作者信息

Nakagawa Y, Hori H, Yamamoto I, Terada H

机构信息

Faculty of Pharmaceutical Science, Okayama University, Japan.

出版信息

Biol Pharm Bull. 1993 Nov;16(11):1061-4. doi: 10.1248/bpb.16.1061.

Abstract

The bleaching of cyanine-type pentamethine trinuclear dyes by active oxygen species (AOS), superoxide and hydroxyl radical, were studied under the xanthine-xanthine oxidase system and the Fenton reaction, respectively. The gradual bleaching of dyes occurred as the result of superoxide produced in the xanthine-xanthine oxidase system. However, the bleaching of cyanine dyes by Fenton reagent varied depending on the reaction conditions. If a normal Fenton reaction of Fe(II) and hydrogen peroxide (H2O2) took place, a hydroxyl radical was generated instantly. A Fenton reaction with an excess of [H2O2] over [Fe(II)] resulted in a gradual bleaching of the dye initiated by the hydroxyl radical, Fe(III) and H2O2. In this reaction, cyanine dyes with shorter side chains were bleached faster than those with longer ones. We controlled the Fenton reaction condition (Fe(II) or Fe(IIO)/H2O2 at pH 3.5 in the dark) to generate a specific AOS such as a hydroxyl radical (.OH) or superoxide (.O2-). Studies using xanthine-xanthine oxidase (pH 7.8), the Fe(II)-dipyridyl complex and various scavengers such as superoxide dismutase (SOD) and hyaluronic acid, revealed that .O2- was the primary radical responsible for this controlled Fenton reaction. This finding shows that this controlled Fenton reaction would be an effective AOS generation method, and that cyanine dyes may be hopeful probes for the detection of AOS.

摘要

分别在黄嘌呤 - 黄嘌呤氧化酶系统和芬顿反应条件下,研究了活性氧(AOS)、超氧阴离子和羟基自由基对花菁型五甲川三核染料的漂白作用。在黄嘌呤 - 黄嘌呤氧化酶系统中产生的超氧阴离子导致了染料的逐渐褪色。然而,芬顿试剂对花菁染料的漂白作用因反应条件而异。如果发生Fe(II)与过氧化氢(H₂O₂)的正常芬顿反应,会立即产生羟基自由基。当[H₂O₂]过量于[Fe(II)]时的芬顿反应会导致由羟基自由基、Fe(III)和H₂O₂引发的染料逐渐褪色。在该反应中,侧链较短的花菁染料比侧链较长的褪色更快。我们控制芬顿反应条件(在黑暗中pH 3.5时的Fe(II)或Fe(IIO)/H₂O₂)以生成特定的活性氧,如羟基自由基(·OH)或超氧阴离子(·O₂⁻)。使用黄嘌呤 - 黄嘌呤氧化酶(pH 7.8)、Fe(II) - 联吡啶配合物以及各种清除剂如超氧化物歧化酶(SOD)和透明质酸进行的研究表明,·O₂⁻是这种可控芬顿反应的主要自由基。这一发现表明,这种可控芬顿反应将是一种有效的活性氧生成方法,并且花菁染料可能是检测活性氧的有前景的探针。

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