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酿酒酵母的一种5'-3'核酸外切酶是线性DNA分子间具有重叠同源性的体外重组所必需的。

A 5'-3' exonuclease from Saccharomyces cerevisiae is required for in vitro recombination between linear DNA molecules with overlapping homology.

作者信息

Huang K N, Symington L S

机构信息

Institute of Cancer Research, Columbia University College of Physicians and Surgeons, New York, New York 10032.

出版信息

Mol Cell Biol. 1993 Jun;13(6):3125-34. doi: 10.1128/mcb.13.6.3125-3134.1993.

Abstract

When two linear DNA molecules with overlapping, homologous ends were incubated with a yeast nuclear extract, they recombined at the region of homology to produce a joint molecule. We have identified a 5'-3' exonuclease in the extract that is likely to be responsible for the formation of the observed product. We propose that the exonuclease degrades each substrate to reveal regions of complementary sequence which anneal to form a recombinant product. Consistent with this model, we have partially purified the activity that promotes joint molecule formation and found it to cofractionate with a 5'-3' exonuclease activity through three consecutive chromatography steps. We have further characterized the reaction to determine the optimal length of homology. Substrates with homologous terminal overlaps of 29 to 958 bp were capable of product formation, whereas substrates with longer overlaps were not. Extracts prepared from a number of recombination-defective or nuclease-deficient strains revealed no defect in exonuclease activity, indicating that the reaction is likely to be dependent upon the product of an as yet unidentified gene.

摘要

当将两个具有重叠同源末端的线性DNA分子与酵母核提取物一起温育时,它们在同源区域发生重组以产生一个连接分子。我们在提取物中鉴定出一种5'-3'核酸外切酶,它可能负责观察到的产物的形成。我们提出,该核酸外切酶降解每个底物以暴露出互补序列区域,这些区域退火形成重组产物。与该模型一致,我们已部分纯化了促进连接分子形成的活性,并发现它在三个连续的色谱步骤中与5'-3'核酸外切酶活性共分级分离。我们进一步对该反应进行了表征,以确定同源性的最佳长度。具有29至958 bp同源末端重叠的底物能够形成产物,而具有更长重叠的底物则不能。从许多重组缺陷或核酸酶缺陷菌株制备的提取物未显示核酸外切酶活性有缺陷,这表明该反应可能依赖于一个尚未鉴定的基因的产物。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/a5bb/359747/bc54fdeb43dc/molcellb00018-0016-a.jpg

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