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拟南芥一种新型蓝色荧光突变体揭示了内源基因家族的表观遗传控制。

Epigenetic control of an endogenous gene family is revealed by a novel blue fluorescent mutant of Arabidopsis.

作者信息

Bender J, Fink G R

机构信息

Whitehead Institute for Biomedical Research, Cambridge, Massachusetts, USA.

出版信息

Cell. 1995 Dec 1;83(5):725-34. doi: 10.1016/0092-8674(95)90185-x.

Abstract

The Wassilewskija strain of Arabidopsis has four genes encoding the tryptophan enzyme phosphoribosylanthranilate isomerase (PAI) located at three unlinked sites. These four PAI genes are methylated over their regions of DNA homology. When PAI copy number is reduced by deletion of two tandemly arrayed genes (MePAI1-PAI4), a mutant with fluorescent, tryptophan-deficient phenotypes results, because the two remaining methylated PAI genes (MePAI2 and MePAI3) supply insufficient PAI activity. These two methylated genes can be inherited through meiosis, even when they are segregated away from each other in crosses to a strain with unmethylated PAI genes. However, the mutant phenotypes conferred by the methylated PAI genes are unstable, and mutant plants yield occasional revertant somatic sectors and progeny. Revertant lines display coordinately reduced methylation of both PAI2 and PAI3, implying that this hypomethylation acts in a concerted manner across the genome rather than at individual sites.

摘要

拟南芥的瓦西列夫斯基株系有四个编码色氨酸酶磷酸核糖基邻氨基苯甲酸异构酶(PAI)的基因,位于三个不连锁的位点。这四个PAI基因在其DNA同源区域发生甲基化。当通过缺失两个串联排列的基因(MePAI1 - PAI4)使PAI拷贝数减少时,会产生具有荧光、色氨酸缺陷表型的突变体,因为剩下的两个甲基化PAI基因(MePAI2和MePAI3)提供的PAI活性不足。这两个甲基化基因可通过减数分裂遗传,即使在与具有未甲基化PAI基因的株系杂交时它们彼此分离。然而,甲基化PAI基因赋予的突变表型不稳定,突变植株偶尔会产生回复体体细胞区和后代。回复系显示PAI2和PAI3的甲基化同时降低,这意味着这种低甲基化以协同方式作用于整个基因组而非个别位点。

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