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大肠杆菌中耐碱性诱导的调控方面。

Regulatory aspects of alkali tolerance induction in Escherichia coli.

作者信息

Rowbury R J, Lazim Z, Goodson M

机构信息

Biology Department (Darwin), University College London, UK.

出版信息

Lett Appl Microbiol. 1996 Jun;22(6):429-32. doi: 10.1111/j.1472-765x.1996.tb01196.x.

Abstract

Escherichia coli shifted from external pH (pH(O)) 7.0 to pH(O) 8.5-9.5 rapidly becomes tolerant to pH(O) 10.0-11.5, induction of tolerance (alkali habituation) being dependent on periplasmic or external alkalinization with either NaOH or KOH. Induction needs protein synthesis and makes organisms resistant to DNA damage by alkali and better able to repair any damage that occurs. Induction of tolerance was reduced by glucose (not reversed by cAMP) and by amiloride, was dependent on DNA gyrase and was abolished by fur and himA lesions (the latter suggests IHF involvement). Tolerance induction was not prevented by L-leucine, FeCl3 or FeSO4 nor by hns or relA mutations. Habituation probably involves attachment of IHF upstream of the promoter leading to DNA bending which switches on transcription. Habituation is aberrant in nhaA mutants, so ability to resist alkali damage may only arise if NhaA is induced, with extrusion of Na+ by this antiporter during alkali challenge. In accord with one tolerance component involving NhaA induction, beta-galactosidase formation from nhaA-lacZ fusions at pH(O) 9.0 was inhibited by glucose and amiloride.

摘要

从外部pH值(pH(O))7.0转变为pH(O) 8.5 - 9.5的大肠杆菌会迅速变得耐受pH(O) 10.0 - 11.5,耐受性的诱导(碱适应)取决于用NaOH或KOH进行的周质或外部碱化。诱导需要蛋白质合成,并使生物体对碱引起的DNA损伤具有抗性,并且更能修复发生的任何损伤。葡萄糖(cAMP不能逆转)和氨氯吡咪会降低耐受性的诱导,其依赖于DNA促旋酶,并且fur和himA损伤会消除这种诱导(后者表明整合宿主因子(IHF)参与其中)。L - 亮氨酸、FeCl3或FeSO4以及hns或relA突变均不能阻止耐受性诱导。适应可能涉及IHF附着在启动子上游导致DNA弯曲,从而开启转录。在nhaA突变体中适应是异常的,所以只有当NhaA被诱导,并且在碱攻击期间通过这种反向转运蛋白排出Na+时,才可能产生抵抗碱损伤的能力。与涉及NhaA诱导的一种耐受性成分一致,在pH(O) 9.0时,来自nhaA - lacZ融合体的β - 半乳糖苷酶形成受到葡萄糖和氨氯吡咪的抑制。

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