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GTP在胰腺胰岛葡萄糖诱导的磷脂酶C激活中的作用。

Role for GTP in glucose-induced phospholipase C activation in pancreatic islets.

作者信息

Vadakekalam J, Rabaglia M E, Chen Q H, Metz S A

机构信息

Department of Medicine, University of Wisconsin, Madison, USA.

出版信息

Am J Physiol. 1996 Jul;271(1 Pt 1):E85-95. doi: 10.1152/ajpendo.1996.271.1.E85.

Abstract

We have previously demonstrated a permissive role for GTP in insulin secretion; in the current studies, we examined the effect of GTP on phospholipase C (PLC) activation to explore one possible mechanism for that observation. In rat islets preexposed to the GTP synthesis inhibitors mycophenolic acid (MPA) or mizoribine (MZ), PLC activation induced by 16.7 mM glucose (or by 20 mM alpha-ketoisocaproic acid) was inhibited 63% without altering the labeling of phosphoinositide substrates. Provision of guanine, which normalizes islet GTP content and insulin release, prevented the inhibition of PLC by MPA. Glucose-induced phosphoinositide hydrolysis was blocked by removal of extracellular Ca2+ or by diazoxide. PLC induced directly by Ca2+ influx (i.e., 40 mM K+) was reduced 42% in MPA-pretreated islets but without inhibition of the concomitant insulin release. These data indicate that glucose-induced PLC activation largely reflects Ca2+ entry and demonstrate (for the first time in intact cells) that adequate GTP is necessary for glucose (and Ca(2+)-)-induced PLC activation but not for maximal Ca(2+)-induced exocytosis.

摘要

我们之前已经证明了GTP在胰岛素分泌中具有允许作用;在当前的研究中,我们研究了GTP对磷脂酶C(PLC)激活的影响,以探索这一观察结果的一种可能机制。在预先暴露于GTP合成抑制剂霉酚酸(MPA)或咪唑立宾(MZ)的大鼠胰岛中,由16.7 mM葡萄糖(或20 mMα-酮异己酸)诱导的PLC激活被抑制了63%,而磷脂酰肌醇底物的标记未发生改变。提供鸟嘌呤可使胰岛GTP含量和胰岛素释放恢复正常,从而防止MPA对PLC的抑制。通过去除细胞外Ca2+或二氮嗪可阻断葡萄糖诱导的磷脂酰肌醇水解。在MPA预处理的胰岛中,由Ca2+内流直接诱导的PLC(即40 mM K+)减少了42%,但并未抑制伴随的胰岛素释放。这些数据表明,葡萄糖诱导的PLC激活很大程度上反映了Ca2+的内流,并(首次在完整细胞中)证明充足的GTP对于葡萄糖(和Ca(2 +)-)诱导的PLC激活是必需的,但对于最大程度的Ca(2 +)-诱导的胞吐作用则不是必需的。

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