Kanazawa H, Fujimoto S, Ohara A
Kyoto Pharmaceutical University, Japan.
Biol Pharm Bull. 1995 Sep;18(9):1179-83. doi: 10.1248/bpb.18.1179.
The mechanism of inactivation of cholinesterase (EC 3.1.1.8) by the Cu2+ -ascorbic acid (AsA) system was investigated. Incubation of the enzyme with the Cu2+ -AsA system under aerobic conditions resulted in an irreversible loss of enzyme activity. At low concentrations of Cu2+, the extent of inactivation showed the same dependence in accordance with the extent of oxidation of AsA. Saturation kinetics were observed with respect to the concentration of AsA. No change in the dissociation constant of the enzyme-AsA complex was observed at various concentrations of Cu2+. Catalase at a low concentration partially protected the enzyme from the inactivation, but did not affect the oxidation of AsA. In addition, catalase at a high concentration completely protected both the enzyme from inactivation and the AsA from oxidation. Both thiourea and thiocyanate completely protected the enzyme from the inactivation, while AsA was partially oxidized only in the initial phase. Our proposed mechanism for the inactivation of an enzyme by the Cu2+ -AsA system is as follows. A ternary complex involving the enzyme, Cu2+ and AsA is formed. This is followed by a redox reaction within the complex which generates a superoxide (.O2-) and hydrogen peroxide (H2O2). The H2O2 then reacts with .O2- in a Haber-Weiss reaction producing the hydroxyl radical (.OH). Another role of H2O2 is the conversion of the reduced Cu+ within the complex to Cu2+. Thus, repeated cycles of the redox reaction between the Cu2+ and AsA take place at the same locus, producing multiple .OH, which causes its complete inactivation.
研究了Cu2 + -抗坏血酸(AsA)体系使胆碱酯酶(EC 3.1.1.8)失活的机制。在有氧条件下,将该酶与Cu2 + -AsA体系一起孵育会导致酶活性的不可逆丧失。在低浓度的Cu2 +下,失活程度与AsA的氧化程度呈现相同的依赖性。观察到AsA浓度的饱和动力学。在不同浓度的Cu2 +下,未观察到酶-AsA复合物解离常数的变化。低浓度的过氧化氢酶可部分保护该酶免于失活,但不影响AsA的氧化。此外,高浓度的过氧化氢酶可完全保护该酶免于失活以及AsA免于氧化。硫脲和硫氰酸盐均可完全保护该酶免于失活,而AsA仅在初始阶段被部分氧化。我们提出的Cu2 + -AsA体系使酶失活的机制如下。形成了一种包含酶、Cu2 +和AsA的三元复合物。随后复合物内发生氧化还原反应,产生超氧阴离子(·O2-)和过氧化氢(H2O2)。然后H2O2在哈伯-维伊斯反应中与·O2-反应生成羟基自由基(·OH)。H2O2的另一个作用是将复合物内还原的Cu +转化为Cu2 +。因此,Cu2 +和AsA之间的氧化还原反应在同一位置重复进行,产生多个·OH,从而导致其完全失活。