Nagata O
Department of Anesthesiology, Faculty of Medicine, University of Tokyo.
Masui. 1996 Nov;45(11):1367-71.
When comparing the means of more than three groups, we first have to carry out an analysis of variance (ANOVA) to confirm whether all of the means of each group are equal, and we then have to evaluate all possible pairwise comparisons with multiple comparison procedures. If we use only the unpaired t-test for all pairwise comparisons without ANOVA and multiple comparison procedures, we are more likely not only to erroneously conclude that two means in a pair are significantly different when actually they are not, but also to create a contradiction between pairs of means with large differences which are not considered significant, and pairs of means with small differences which are considered significant. In this article, I discuss two problems in comparing the means of multiple groups by presenting an example in which I apply unpaired t-test on data that should be analyzed by ANOVA and multiple comparison procedures.
在比较三组以上的均值时,我们首先必须进行方差分析(ANOVA),以确认每组的所有均值是否相等,然后我们必须使用多重比较程序评估所有可能的两两比较。如果我们在没有进行方差分析和多重比较程序的情况下,仅对所有两两比较使用不成对t检验,那么我们不仅更有可能错误地得出一对均值存在显著差异的结论(而实际上它们并无差异),而且还会在被认为不显著的差异较大的均值对与被认为显著的差异较小的均值对之间产生矛盾。在本文中,我通过给出一个示例来讨论在比较多组均值时出现的两个问题,在该示例中,我对本应通过方差分析和多重比较程序进行分析的数据应用了不成对t检验。