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在霍利迪连接体底物的拆分过程中,Flp重组酶的四聚体会使其中的三聚体失活。

A tetramer of the Flp recombinase silences the trimers within it during resolution of a Holliday junction substrate.

作者信息

Lee J, Jayaram M

机构信息

Department of Microbiology and Institute of Cell and Molecular Biology, University of Texas at Austin, 78712, USA.

出版信息

Genes Dev. 1997 Sep 15;11(18):2438-47. doi: 10.1101/gad.11.18.2438.

Abstract

Recombination catalyzed by the Flp site-specific recombinase involves breakage and joining of four DNA strands between two target substrates. The reaction is carried out in two steps of pairwise strand exchanges by a DNA-protein assembly in which four Flp monomers act cooperatively to execute strand cleavage and joining. Two models for recombination have been proposed. In the trimer model, the two active sites required for each step are assembled from three Flp monomers. In the tetramer (or dimer of asymmetric dimers) model, the two active sites are assembled from four Flp monomers, two monomers each contributing one active site. Experiments in which the two models challenge each other reveal that, within the Flp tetramer arranged on a Holliday junction, the two active sites required for its resolution are derived from all four, rather than three, Flp monomers. Thus, the relative protein subunit configuration of the tetramer silences the trimers within it by excluding them from assembling a functional active site pair.

摘要

由Flp位点特异性重组酶催化的重组涉及两个靶底物之间四条DNA链的断裂和连接。该反应通过DNA-蛋白质组装以成对链交换的两个步骤进行,其中四个Flp单体协同作用以执行链切割和连接。已经提出了两种重组模型。在三聚体模型中,每个步骤所需的两个活性位点由三个Flp单体组装而成。在四聚体(或不对称二聚体的二聚体)模型中,两个活性位点由四个Flp单体组装而成,每个单体贡献一个活性位点。两种模型相互挑战的实验表明,在排列在霍利迪连接体上的Flp四聚体中,其拆分所需的两个活性位点来自所有四个而非三个Flp单体。因此,四聚体的相对蛋白质亚基构型通过将三聚体排除在功能性活性位点对的组装之外而使其沉默。

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