Suppr超能文献

定量LOD评分:人类同胞对中定量性状的排除与连锁分析的检验统计量和样本量

The quantitative LOD score: test statistic and sample size for exclusion and linkage of quantitative traits in human sibships.

作者信息

Page G P, Amos C I, Boerwinkle E

机构信息

Human Genetics Center, University of Texas School of Public Health, M.D. Anderson Cancer Center, Houston, TX 77030, USA.

出版信息

Am J Hum Genet. 1998 Apr;62(4):962-8. doi: 10.1086/301783.

Abstract

We present a test statistic, the quantitative LOD (QLOD) score, for the testing of both linkage and exclusion of quantitative-trait loci in randomly selected human sibships. As with the traditional LOD score, the boundary values of 3, for linkage, and -2, for exclusion, can be used for the QLOD score. We investigated the sample sizes required for inferring exclusion and linkage, for various combinations of linked genetic variance, total heritability, recombination distance, and sibship size, using fixed-size sampling. The sample sizes required for both linkage and exclusion were not qualitatively different and depended on the percentage of variance being linked or excluded and on the total genetic variance. Information regarding linkage and exclusion in sibships larger than size 2 increased as approximately all possible pairs n(n-1)/2 up to sibships of size 6. Increasing the recombination (theta) distance between the marker and the trait loci reduced empirically the power for both linkage and exclusion, as a function of approximately (1-2theta)4.

摘要

我们提出了一种检验统计量,即定量对数优势比(QLOD)分数,用于在随机选择的人类同胞对中检测数量性状位点的连锁和排除情况。与传统的对数优势比分数一样,连锁的临界值3和排除的临界值-2可用于QLOD分数。我们使用固定大小抽样,研究了在连锁遗传方差、总遗传率、重组距离和同胞对大小的各种组合下,推断排除和连锁所需的样本量。连锁和排除所需的样本量在性质上没有差异,并且取决于被连锁或排除的方差百分比以及总遗传方差。同胞对大于2时,关于连锁和排除的信息随着大约所有可能的对子数n(n - 1)/2增加,直至同胞对大小为6。经验上,增加标记与性状位点之间的重组(θ)距离会降低连锁和排除的功效,其函数关系约为(1 - 2θ)4 。

相似文献

本文引用的文献

文献检索

告别复杂PubMed语法,用中文像聊天一样搜索,搜遍4000万医学文献。AI智能推荐,让科研检索更轻松。

立即免费搜索

文件翻译

保留排版,准确专业,支持PDF/Word/PPT等文件格式,支持 12+语言互译。

免费翻译文档

深度研究

AI帮你快速写综述,25分钟生成高质量综述,智能提取关键信息,辅助科研写作。

立即免费体验