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果蝇的无翅基因编码一种能激活JAK信号通路的分泌蛋白。

Drosophila unpaired encodes a secreted protein that activates the JAK signaling pathway.

作者信息

Harrison D A, McCoon P E, Binari R, Gilman M, Perrimon N

机构信息

Department of Genetics, Boston, Massachusetts 02115 USA.

出版信息

Genes Dev. 1998 Oct 15;12(20):3252-63. doi: 10.1101/gad.12.20.3252.

Abstract

In vertebrates, many cytokines and growth factors have been identified as activators of the JAK/STAT signaling pathway. In Drosophila, JAK and STAT molecules have been isolated, but no ligands or receptors capable of activating the pathway have been described. We have characterized the unpaired (upd) gene, which displays the same distinctive embryonic mutant defects as mutations in the Drosophila JAK (hopscotch) and STAT (stat92E) genes. Upd is a secreted protein, associated with the extracellular matrix, that activates the JAK pathway. We propose that Upd is a ligand that relies on JAK signaling to stimulate transcription of pair-rule genes in a segmentally restricted manner in the early Drosophila embryo.

摘要

在脊椎动物中,许多细胞因子和生长因子已被鉴定为JAK/STAT信号通路的激活剂。在果蝇中,JAK和STAT分子已被分离出来,但尚未描述能够激活该通路的配体或受体。我们已经对无配对(upd)基因进行了表征,该基因表现出与果蝇JAK(跳房子)和STAT(stat92E)基因突变相同的独特胚胎突变缺陷。Upd是一种与细胞外基质相关的分泌蛋白,可激活JAK通路。我们提出,Upd是一种配体,它依赖JAK信号传导,以分段受限的方式刺激果蝇早期胚胎中配对规则基因的转录。

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