Cooper D W
Aust J Biol Sci. 1976 Jul;29(3):245-50. doi: 10.1071/bi9760245.
Female kangaroos and perhaps other female marsupials have a unique form of dosage compensation for X-linked genes in their soma. In these animals the paternal X is inactive. Heterozygote females therefore have the phenotype of one or the other of the homozygotes, with the allele which is expressed coming from their mother. The unexpressed paternally derived allele may, however, be transmitted to the next generation in the usual Mendelian manner and there be expressed. Such a combination of haploid phenotypic expression and diploid genotypic behaviour on the part of X-linked genes in kangaroos makes their population genetics unique. This paper examines the possibilities for balancing selection in the kangaroo X chromosome system and shows that balanced polymorphisms are unlikely to occur. If 1 - a, 1, 1 - b and 1 are the selection coefficients of the alpha1 females, alpha2 females, alpha1 males and alpha2 males respectively (where alpha1 is the phenotype when A1 is expressed and alpha2 the phenotype when A2 is expressed), then the equilibrium is reached when the gene frequency of A1 in females = 0-5(a-1 + b-1), which takes values between 0 and 1 for only a few of the biologically likely values of a and b.
雌性袋鼠以及或许其他有袋类雌性动物在其体细胞中对X连锁基因有一种独特的剂量补偿形式。在这些动物中,父本X染色体是失活的。因此,杂合子雌性具有纯合子之一的表型,其表达的等位基因来自它们的母亲。然而,未表达的父本衍生等位基因可能会以通常的孟德尔方式传递给下一代并在那里表达。袋鼠中X连锁基因的这种单倍体表型表达和二倍体基因型行为的组合使其群体遗传学独具特色。本文研究了袋鼠X染色体系统中平衡选择的可能性,并表明平衡多态性不太可能发生。如果1 - a、1、1 - b和1分别是α1雌性、α2雌性、α1雄性和α2雄性的选择系数(其中α1是A1表达时的表型,α2是A2表达时的表型),那么当雌性中A1的基因频率 = 0.5(a - 1 + b - 1)时达到平衡,对于a和b仅有的一些生物学上可能的值,该平衡值在0到1之间。