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同源的小鼠Hox基因Hoxa9、Hoxb9和Hoxd9共同发挥作用,以控制乳腺在妊娠反应中的发育。

Paralogous mouse Hox genes, Hoxa9, Hoxb9, and Hoxd9, function together to control development of the mammary gland in response to pregnancy.

作者信息

Chen F, Capecchi M R

机构信息

Howard Hughes Medical Institute, Department of Human Genetics, University of Utah School of Medicine, Salt Lake City, UT 84112, USA.

出版信息

Proc Natl Acad Sci U S A. 1999 Jan 19;96(2):541-6. doi: 10.1073/pnas.96.2.541.

Abstract

Although the role of Hox genes in patterning the mammalian body plan has been studied extensively during embryonic and fetal development, relatively little is known concerning Hox gene function in adult animals. Analysis of mice with mutant Hoxa9, Hoxb9, and Hoxd9 genes shows that these paralogous genes are required for mediating the expansion and/or differentiation of the mammary epithelium ductal system in response to pregnancy. Mothers with these three mutant genes cannot raise their own pups, but the pups can be rescued by fostering by wild-type mothers. Histologically, the mammary glands of the mutant mothers seem normal before pregnancy but do not develop properly in response to pregnancy and parturition. Hoxa9, Hoxb9, and Hoxd9 are expressed normally in adult mammary glands, suggesting a direct role for these genes in the development of mammary tissue after pregnancy. Because loss-of-function mutations in these Hox genes cause hypoplasia of the mammary gland after pregnancy, it may be productive to look for misexpression of these genes in mammary carcinomas.

摘要

尽管在胚胎和胎儿发育过程中,Hox基因在构建哺乳动物身体结构方面的作用已得到广泛研究,但对于成年动物中Hox基因的功能却知之甚少。对具有突变型Hoxa9、Hoxb9和Hoxd9基因的小鼠进行分析表明,这些同源基因是介导乳腺上皮导管系统在妊娠时发生扩张和/或分化所必需的。携带这三种突变基因的母鼠无法哺育自己的幼崽,但野生型母鼠寄养可挽救这些幼崽。从组织学上看,突变母鼠的乳腺在妊娠前似乎正常,但在妊娠和分娩时不能正常发育。Hoxa9、Hoxb9和Hoxd9在成年乳腺中正常表达,表明这些基因在妊娠后乳腺组织发育中具有直接作用。由于这些Hox基因的功能丧失突变会导致妊娠后乳腺发育不全,因此研究这些基因在乳腺癌中的错误表达可能会有所收获。

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本文引用的文献

1
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Paralogous Hox genes: function and regulation.同源异型盒基因:功能与调控
Annu Rev Genet. 1996;30:529-56. doi: 10.1146/annurev.genet.30.1.529.

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