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在缺失MOR-1外显子1的新型小鼠品系中,海洛因和吗啡-6β-葡萄糖醛酸苷镇痛作用的保留情况。

Retention of heroin and morphine-6 beta-glucuronide analgesia in a new line of mice lacking exon 1 of MOR-1.

作者信息

Schuller A G, King M A, Zhang J, Bolan E, Pan Y X, Morgan D J, Chang A, Czick M E, Unterwald E M, Pasternak G W, Pintar J E

机构信息

Dept. of Neuroscience and Cell Biology, UMDNJ-Robert Wood Johnson Medical School, Piscätaway 08854, USA.

出版信息

Nat Neurosci. 1999 Feb;2(2):151-6. doi: 10.1038/5706.

Abstract

Morphine produces analgesia by activating mu opioid receptors encoded by the MOR-1 gene. Although morphine-6 beta-glucuronide (M6G), heroin and 6-acetylmorphine also are considered mu opioids, recent evidence suggests that they act through a distinct receptor mechanism. We examined this question in knockout mice containing disruptions of either the first or second coding exon of MOR-1. Mice homozygous for either MOR-1 mutation were insensitive to morphine. Heroin, 6-acetylmorphine and M6G still elicited analgesia in the exon-1 MOR-1 mutant, which also showed specific M6G binding, whereas M6G and 6-acetylmorphine were inactive in the exon-2 MOR-1 mutant. These results provide genetic evidence for a unique receptor site for M6G and heroin analgesia.

摘要

吗啡通过激活由MOR-1基因编码的μ阿片受体产生镇痛作用。虽然吗啡-6β-葡萄糖醛酸苷(M6G)、海洛因和6-乙酰吗啡也被认为是μ阿片类药物,但最近的证据表明它们通过不同的受体机制起作用。我们在含有MOR-1第一或第二编码外显子破坏的基因敲除小鼠中研究了这个问题。MOR-1突变纯合子小鼠对吗啡不敏感。海洛因、6-乙酰吗啡和M6G在外显子1 MOR-1突变体中仍能引起镇痛作用,该突变体也显示出特异性M6G结合,而M6G和6-乙酰吗啡在外显子2 MOR-1突变体中无活性。这些结果为M6G和海洛因镇痛的独特受体位点提供了遗传学证据。

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