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LbetaT2促性腺激素细胞会对活性A做出反应,分泌促卵泡激素(FSH)。

LbetaT2 gonadotroph cells secrete follicle stimulating hormone (FSH) in response to active A.

作者信息

Graham K E, Nusser K D, Low M J

机构信息

Division of Endocrinology, Oregon Health Sciences University, Portland, Oregon 97201, USA.

出版信息

J Endocrinol. 1999 Sep;162(3):R1-5. doi: 10.1677/joe.0.162r001.

DOI:10.1677/joe.0.162r001
PMID:10467239
Abstract

Secretion of luteinizing hormone in response to gonadotropin releasing hormone (GnRH) has been described in the recently developed LbetaT2 gonadotroph cell line. We evaluated the expression of follicle stimulating hormone (FSH)beta mRNA and secretion of FSH from LbetaT2 cells in response to GnRH and activin A. LbetaT2 cells were treated with activin A in doses from 0 to 50 ng/ml, with or without a daily 10 nM GnRH pulse, or with GnRH alone. FSH secretion was stimulated over 6-fold by concomitant GnRH and activin A in a dose-responsive fashion at 72 h of treatment. FSHbeta mRNA was detectable by ribonuclease protection assay only in cells treated with activin A with or without GnRH. The demonstration of FSHbeta gene expression in LbetaT2 cells further validates these cells as mature, differentiated gonadotrophs and as an important tool for the study of gonadotroph physiology.

摘要

在最近建立的LbetaT2促性腺激素细胞系中,已描述了促黄体生成素对促性腺激素释放激素(GnRH)的分泌反应。我们评估了促卵泡激素(FSH)β mRNA的表达以及LbetaT2细胞对GnRH和激活素A的反应中FSH的分泌。用0至50 ng/ml剂量的激活素A处理LbetaT2细胞,有或没有每日10 nM GnRH脉冲,或仅用GnRH处理。在处理72小时时,GnRH和激活素A同时以剂量反应方式刺激FSH分泌超过6倍。仅在用激活素A处理且有或没有GnRH的细胞中,通过核糖核酸酶保护试验可检测到FSHβ mRNA。LbetaT2细胞中FSHβ基因表达的证明进一步证实了这些细胞是成熟的、分化的促性腺激素细胞,也是研究促性腺激素细胞生理学的重要工具。

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