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膳食多不饱和脂肪与饱和脂肪在乳腺癌发生中的关系。

Dietary polyunsaturated fat versus saturated fat in relation to mammary carcinogenesis.

作者信息

Carroll K K, Hopkins G J

出版信息

Lipids. 1979 Feb;14(2):155-8. doi: 10.1007/BF02533866.

Abstract

High levels of dietary fat have been shown to promote the development of mammary tumors induced in rats by 7,12-dimethylbenz(alpha)anthracene, and polyunsaturated fats were found to be more effective than saturated fats. In further studies it was found that diets containing 3% sunflowerseed oil (polyunsaturated fat) and 17% beef tallow or coconut oil (saturated fats) enhance tumorigenesis as much as a diet containing 20% sunflowerseed oil. Rats on these diets developed at least twice as many tumors as those fed diets containing either 3% sunflowerseed oil or 20% of the saturated fats alone. These results are in accord with human epidemiological data which show that breast cancer mortality in different countries is positively correlated with total fat intake but not with intake of polyunsaturated fat. Total fat intake varies greatly in different countries, but most human diets probably contain levels of polyunsaturated fat at least equivalent to 3% sunflowerseed oil.

摘要

高水平的膳食脂肪已被证明会促进7,12-二甲基苯并(a)蒽诱导的大鼠乳腺肿瘤的发展,并且发现多不饱和脂肪比饱和脂肪更有效。在进一步的研究中发现,含有3%向日葵油(多不饱和脂肪)和17%牛脂或椰子油(饱和脂肪)的饮食与含有20%向日葵油的饮食一样能增强肿瘤发生。食用这些饮食的大鼠所患肿瘤至少是仅食用含有3%向日葵油或20%饱和脂肪饮食的大鼠的两倍。这些结果与人类流行病学数据一致,该数据表明不同国家的乳腺癌死亡率与总脂肪摄入量呈正相关,而与多不饱和脂肪的摄入量无关。不同国家的总脂肪摄入量差异很大,但大多数人类饮食中多不饱和脂肪的含量可能至少相当于3%的向日葵油。

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